The mixture which shows positive deviation from Raoult's law is:
Answer: (C) Ethanol + Acetone. \textbf{Answer:} (C) Ethanol + Acetone \textbf{Solution:} Positive deviation occurs when A-B interactions are \textbf{weaker} than A-A and B-B interactions, raising the vapour pressure above the Raoult's law prediction.
- A.Acetone + Chloroform
- B.Chloroethane + Bromoethane
- C.Ethanol + Acetone✓
- D.Benzene + Toluene
Correct Answer
(C) Ethanol + Acetone
Solution & Explanation
\textbf{Answer:} (C) Ethanol + Acetone \textbf{Solution:} Positive deviation occurs when A-B interactions are \textbf{weaker} than A-A and B-B interactions, raising the vapour pressure above the Raoult's law prediction. In Ethanol + Acetone, acetone molecules break the hydrogen bonding present in pure ethanol, weakening the overall interactions → positive deviation. Acetone + Chloroform () is the standard \textbf{negative} deviation pair (H-bonding forms between them). Chloroethane + Bromoethane and Benzene + Toluene behave nearly ideally.
