NEET 2023 Phase 1 · ChemistryPrevious Year Question

An ideal gas expands isothermally from $1 0^{- 3} m^{3}$ to $1 0^{- 2} m^{3}$ at $300 K$ against a constant pressure of $1 0^{5} N m^{- 2}$ . The work done on the gas is:

Answer: (B) $- 900 J$ . \textbf{Answer:} (B) $- 900 J$ \textbf{Solution:} Work done on the gas against a constant external pressure: $w = - p_{e x t} (V_{f} - V_{i}) = - 1 0^{5} \times (1 0^{- 2} - 1 0^{- 3}) = - 1 0^{5} \times (9 \times 1 0^{- 3}) = - 900 J$ .

A. $+ 270 kJ$
B. $- 900 J$ ✓
C. $+ 900 kJ$
D. $- 900 kJ$

Correct Answer

(B) $- 900 J$

Solution & Explanation

\textbf{Answer:} (B) $- 900 J$ \textbf{Solution:} Work done on the gas against a constant external pressure: $w = - p_{e x t} (V_{f} - V_{i}) = - 1 0^{5} \times (1 0^{- 2} - 1 0^{- 3}) = - 1 0^{5} \times (9 \times 1 0^{- 3}) = - 900 J$ . The negative sign indicates the gas does work on the surroundings during expansion. Mapped: source numeric answer '2' → option B.

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An ideal gas expands isothermally from 10−3 m3 to 10−2 m3 at 300 K against a constant pressure of 105 Nm−2. The work done on the gas is:

Solution & Explanation

More NEET PYQ solutions

An ideal gas expands isothermally from $1 0^{- 3} m^{3}$ to $1 0^{- 2} m^{3}$ at $300 K$ against a constant pressure of $1 0^{5} N m^{- 2}$ . The work done on the gas is: