NEET 2023 Phase 1 · ChemistryCyanohydrinPrevious Year Question

Complete the following reaction. Cyclohexanone $[A]$ reacts with $HCN$ to give $[B]$ , which on treatment with conc. $H X_{2} SO X_{4}$ /heat gives $[C]$ . $C$ is:

Answer: (D) (D) cyclohexane carboxylic acid (ring with $- COOH$ ). \textbf{Answer:} (D) cyclohexane carboxylic acid \textbf{Solution:} Cyclohexanone ( $A$ ) undergoes nucleophilic addition of $HCN$ to give the cyanohydrin 1-hydroxycyclohexane-1-carbonitrile ( $B$ , ring bearing $- OH$ and $- CN$ ).

A.(A) cyclohexanol (ring with $- OH$ )
B.(B) cyclohexane carbaldehyde (ring with $- CHO$ )
C.(C) 1-hydroxycyclohexane-1-carbonitrile (ring with $- OH$ and $- CN$ )
D.(D) cyclohexane carboxylic acid (ring with $- COOH$ )✓

Correct Answer

(D) (D) cyclohexane carboxylic acid (ring with $- COOH$ )

Solution & Explanation

\textbf{Answer:} (D) cyclohexane carboxylic acid \textbf{Solution:} Cyclohexanone ( $A$ ) undergoes nucleophilic addition of $HCN$ to give the cyanohydrin 1-hydroxycyclohexane-1-carbonitrile ( $B$ , ring bearing $- OH$ and $- CN$ ). On heating with conc. $H X_{2} SO X_{4}$ , the nitrile group is hydrolysed (with loss of the alpha-hydroxy group) to give cyclohexane carboxylic acid ( $C$ , ring bearing $- COOH$ ).

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Complete the following reaction. Cyclohexanone [A] reacts with HCN to give [B], which on treatment with conc. HX2​SOX4​/heat gives [C]. C is:

Solution & Explanation

More NEET PYQ solutions

Complete the following reaction. Cyclohexanone $[A]$ reacts with $HCN$ to give $[B]$ , which on treatment with conc. $H X_{2} SO X_{4}$ /heat gives $[C]$ . $C$ is: