NEET 2022 · ChemistryCyanohydrinPrevious Year Question
Match List-I with List-II. List-I (Products formed): (a) Cyanohydrin (b) Acetal (c) Schiff's base (d) Oxime List-II (Reaction of carbonyl compound with): (i) (ii) (iii) alcohol (iv) Choose the correct answer from the options given below:
Answer: (D) (D) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i). \textbf{Answer:} (D) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i) \textbf{Solution:} Carbonyl + gives a cyanohydrin, so (a)-(iv).
- A.(A) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
- B.(B) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
- C.(C) (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
- D.(D) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)✓
Correct Answer
(D) (D) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
Solution & Explanation
\textbf{Answer:} (D) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i) \textbf{Solution:} Carbonyl + gives a cyanohydrin, so (a)-(iv). Carbonyl + 2 alcohol gives an acetal, so (b)-(iii). Carbonyl + primary amine gives a Schiff's base (imine, ), so (c)-(ii). Carbonyl + hydroxylamine gives an oxime (), so (d)-(i).
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