NEET 2026 (Phase 1) · ChemistryPrevious Year Question

Identify the correct statements: (A) The molality of 2.5 g of ethanoic acid (Molar mass: $60\ \text{g mol}^{-1}$) in 75 g of benzene solution is 0.556 m. (B) The molarity of a solution containing 5 g of \ce{NaOH} (molar mass: $40\ \text{g mol}^{-1}$) in 450 mL of solution is 0.278 M at 298 K. (C) Aquatic species are more comfortable in cold water. (D) The solubility of a gas increases with decrease in pressure. (E) For a binary mixture of A and B, the number of moles of A and B are $n_A$ and $n_B$ respectively. The mole fraction of B will be $x_B = \frac{n_A}{n_A + n_B}$.

  1. A.A, B and C only
  2. B.A and B only
  3. C.A and C only
  4. D.A, D and E only

Correct Answer

(A) A, B and C only

Solution & Explanation

\textbf{Answer:} (A) A, B and C only \textbf{Solution:} (A) Molality $= \dfrac{2.5/60}{75/1000} = \dfrac{0.0417}{0.075} = 0.556\ m$ — correct. (B) Molarity $= \dfrac{5/40}{450/1000} = \dfrac{0.125}{0.45} = 0.278\ M$ — correct. (C) Gas solubility increases as temperature falls, so cold water holds more dissolved \ce{O2}; aquatic species are more comfortable in cold water — correct. (D) Solubility of a gas \textbf{increases with increase} in pressure (Henry's law), not with a decrease — FALSE. (E) The expression $\frac{n_A}{n_A + n_B}$ is actually $x_A$, not $x_B$ — FALSE. Correct statements: A, B and C → option (A).

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