NEET 2026 (Phase 1) · ChemistryPrevious Year Question
Match List-I with List-II: List-I ($n$, $l$) (A) $n=2$, $l=1$ (B) $n=4$, $l=0$ (C) $n=5$, $l=3$ (D) $n=3$, $l=2$ List-II (Orbital) (I) $3d$ (II) $2p$ (III) $4s$ (IV) $5f$ Choose the correct answer from the options given below:
- A.A-IV, B-II, C-III, D-I
- B.A-II, B-III, C-I, D-IV
- C.A-II, B-III, C-IV, D-I✓
- D.A-I, B-II, C-III, D-IV
Correct Answer
(C) A-II, B-III, C-IV, D-I
Solution & Explanation
\textbf{Answer:} (C) A-II, B-III, C-IV, D-I \textbf{Solution:} $l$ gives the sub-shell: $l=0\rightarrow s$, $l=1\rightarrow p$, $l=2\rightarrow d$, $l=3\rightarrow f$. So A ($n=2,l=1$) $= 2p$, B ($n=4,l=0$) $= 4s$, C ($n=5,l=3$) $= 5f$, D ($n=3,l=2$) $= 3d$. Hence A-II, B-III, C-IV, D-I.
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