Match List-I with List-II: List-I ($n$, $l$) (A) $n=2$, $l=1$ (B) $n=4$, $l=0$ (C) $n=5$, $l=3$ (D) $n=3$, $l=2$ List-II (Orbital) (I) $3d$ (II) $2p$ (III) $4s$ (IV) $5f$ Choose the correct answer from the options given below:

Solution & Explanation

\textbf{Answer:} (C) A-II, B-III, C-IV, D-I \textbf{Solution:} $l$ gives the sub-shell: $l=0\to s$, $l=1\to p$, $l=2\to d$, $l=3\to f$. So A ($n=2,l=1$) $=2p$, B ($n=4,l=0$) $=4s$, C ($n=5,l=3$) $=5f$, D ($n=3,l=2$) $=3d$. Hence A-II, B-III, C-IV, D-I.