Effect of Potential on Photoelectric Current

Physics · Dual Nature Of Radiation And Matter · NEET

When you make the collector plate more positive, the photoelectric current rises and then flattens to a fixed value called the saturation current (all emitted electrons are collected). When you make the collector negative, it repels electrons and the current falls; at a certain negative value called the stopping potential (V0), the current becomes zero. Memory hook: "Push positive to fill it up (saturation), push negative to shut it down (stopping)."
Collector potentialPhotoelectric current+ potential- potential (retard)Saturation currentV0 (stopping)current = 0V=0: small current
Photoelectric current versus collector potential: on the negative side the current falls to zero at the stopping potential V0; on the positive side it rises and flattens to the saturation current. A small current still flows at zero potential.

Your doubts, answered

Why does the photocurrent become constant (saturation) at high positive potential?

Once the collector plate is positive enough, it pulls in every single electron that the metal emits per second. There are no extra electrons left uncollected. So raising the potential more cannot increase the current. That flat maximum is the saturation current. It is fixed by how many electrons are emitted per second, which depends on light intensity, not on the potential.

Does making the plate negative make the current drop to zero right away?

No. A small negative potential only turns back the slowest electrons, so the current drops but is still not zero. As you make the plate more negative, more electrons are turned back and the current keeps falling. Only at one exact value, the stopping potential V0, even the fastest electron is stopped, and the current finally becomes zero.

Is saturation current the same thing as stopping potential?

No, they are opposite ends of the graph. Saturation current is the maximum current on the positive-potential side (all electrons collected). Stopping potential is the negative voltage on the other side that makes the current zero. Saturation current tells you about the NUMBER of electrons (intensity). Stopping potential tells you about the maximum ENERGY of electrons (frequency).

Does the stopping potential depend on intensity or on frequency?

Stopping potential depends only on the frequency (colour) of the light and the metal's work function, not on intensity. Brighter light of the same frequency gives more electrons, so the saturation current goes up, but the fastest electron has the same energy, so V0 stays the same. Increase the frequency and V0 increases (eV0 = h(nu) - work function).

What is the current when the anode potential is exactly zero?

It is small but not zero. Even with no accelerating voltage, some photoelectrons are emitted with enough kinetic energy to reach the collector on their own. So the current is positive at zero potential. You need an actual negative (retarding) potential to bring it down to zero.

⚠️ The NEET trap
Increasing the positive collector potential keeps increasing the photoelectric current.
Current increases only until saturation, then stays constant. Beyond saturation, extra positive potential does nothing because all emitted electrons are already collected.
🧠 After saturation the graph is a flat line, not a rising line. More voltage cannot create more electrons than the metal emits per second.

Real NEET questions

2026 (ReNEET)

A beam of light falls on a metal surface so that photoelectrons are generated. If the power of the light source decreases linearly with time t, then the variation of the photocurrent I and the magnitude of the stopping potential |V| with time is best represented by:

A · I decreases linearly with t; |V| stays constant
B · I decreases; |V| increases
C · I constant; |V| decreases
D · I constant; |V| constant
Solution: Step 1: Power P is proportional to (number of photons per second) x (energy per photon). Step 2: As P falls linearly, the number of photons per second falls linearly, so the number of photoelectrons per second falls linearly. Photocurrent is proportional to electrons per second, so I decreases linearly with t. Step 3: The frequency of the light does not change, so the photon energy and the maximum kinetic energy of electrons do not change. Stopping potential eV0 = Kmax, so |V| stays constant. Answer: A.
2016 (Phase 2)

Photons of energy 5 eV are incident on a cathode C. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A if the stopping potential of A relative to C is:

A · +3 V
B · +4 V
C · -1 V
D · -3 V
Solution: Step 1: Find the work function. Kmax = E - work function, so 2 = 5 - W, giving W = 3 eV. Step 2: For 6 eV photons, Kmax = 6 - 3 = 3 eV. Step 3: To stop the fastest electron, the retarding energy eV0 must equal 3 eV, so V0 = 3 V. Step 4: To repel (retard) electrons, the anode A must be NEGATIVE relative to C, so the stopping potential is -3 V. Answer: D.

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Frequently asked

What is the effect of potential on photoelectric current in one line?

Positive plate potential raises the current up to a fixed saturation value; negative (retarding) potential lowers the current until it reaches zero at the stopping potential V0.

What is saturation current?

The maximum, constant photoelectric current reached when the collector is positive enough to catch every electron emitted per second. It depends on light intensity, not on the potential.

What is stopping potential?

The minimum negative potential on the collector that makes the photoelectric current exactly zero by stopping even the fastest electron. It is set by the light frequency and the metal's work function.

Why is the current not zero at zero potential?

Some photoelectrons leave the metal with enough kinetic energy to reach the collector on their own, so a small current flows even with no accelerating voltage.

Does higher intensity change the stopping potential?

No. Higher intensity raises the saturation current (more electrons) but does not change the stopping potential, because the maximum electron energy depends on frequency, not intensity.