Rate of Heat Produced by Viscous Force at Terminal Velocity

Physics · Mechanical Properties Of Fluids · NEET

At terminal velocity the sphere moves at constant speed, so all the gravitational work goes into heat. The rate of heat produced equals the power lost against the viscous drag: Rate = Force x velocity = (6 pi eta r v) x v = 6 pi eta r v^2. Memory hook: "Power = Drag x Speed". Since terminal velocity v is proportional to r^2, this rate is proportional to r x (r^2)^2 = r^5.
viscous liquidrv (down)drag FAt terminal velocity: speed constantRate of heat = Power = F x v= (6 pi eta r v) x v = 6 pi eta r v^2v is proportional to r^2Rate is proportional to r x r^4 = r^5
A sphere falling at terminal velocity: the viscous drag balances the net downward force, and the power lost against drag (F x v = 6 pi eta r v^2) becomes heat. With v proportional to r^2, the rate of heat scales as r^5.

Your doubts, answered

Why is heat produced at all when the ball moves at constant speed?

The ball keeps falling, so gravity keeps doing positive work on it. At terminal velocity the speed is constant, so the kinetic energy does not change. That means every bit of work gravity does is not going into speed. It is being converted into heat by the viscous force (internal friction of the liquid). So heat is produced continuously even though the ball is not speeding up.

Is the 'rate of heat' the same as power?

Yes. Rate of heat produced means heat produced per second, which is exactly power. Power = Force x velocity. Here the force is the viscous drag F = 6 pi eta r v and the velocity is the terminal velocity v. So Rate of heat = F x v = 6 pi eta r v^2. Watts (joule per second) is the unit.

Why is the rate proportional to r^5 and not r^2 or r^3?

Start from Rate = 6 pi eta r v^2. The r in front gives one power of r. Terminal velocity v is proportional to r^2, so v^2 is proportional to r^4. Multiply: r^1 x r^4 = r^5. A common mistake is to stop at the r in front (giving r^1) or to use v proportional to r^2 only once (giving r^3). You must square v because power uses v^2.

At terminal velocity, does all the gravity work turn into heat?

Not quite all of gravity's work. Some work by gravity is stored as work against buoyancy, but the net driving force equals the drag. The clean way: since speed is constant, net force is zero, so the drag force equals the net downward force. The power delivered by this balance equals drag x velocity, and that entire amount becomes heat. Kinetic energy stays fixed, so nothing is stored as motion.

Do I use v or v squared in the power formula?

Use v squared overall. Power = F x v, and F itself contains one v (because F = 6 pi eta r v grows with speed). So Power = (6 pi eta r v) x v = 6 pi eta r v^2. Students who write Power = 6 pi eta r v (only one v) get the wrong dependence and the wrong answer.

⚠️ The NEET trap
Rate of heat = viscous force = 6 pi eta r v, so it is proportional to r x r^2 = r^3.
Rate of heat is power, not force. Power = F x v = 6 pi eta r v^2, and v is proportional to r^2, so rate is proportional to r x r^4 = r^5.
🧠 'Rate of heat' means heat per second = POWER = Force x speed. Multiply by v one extra time. Then substitute v proportional to r^2 and square it.

Real NEET questions

NEET 2018

A small sphere of radius r falls from rest in a viscous liquid. As a result, heat is produced due to the viscous force. The rate of production of heat, when the sphere attains its terminal velocity, is proportional to:

A · r^5
B · r^2
C · r^3
D · r^4
Solution: Step 1: Terminal velocity of a falling sphere is v = (2/9) x r^2 x (rho_body - rho_liquid) x g / eta, so v is proportional to r^2. Step 2: Rate of heat produced = power dissipated against drag = Force x velocity. Step 3: Viscous drag (Stokes) F = 6 pi eta r v, so Power = F x v = 6 pi eta r v^2. Step 4: Substitute v proportional to r^2, so v^2 is proportional to r^4. Step 5: Power is proportional to r x r^4 = r^5. Answer: r^5 (option A).

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Frequently asked

What is the formula for rate of heat produced at terminal velocity?

Rate of heat = power dissipated = viscous force x terminal velocity = (6 pi eta r v) x v = 6 pi eta r v^2, measured in watts.

Why is the rate of heat proportional to r^5?

Because rate = 6 pi eta r v^2 and terminal velocity v is proportional to r^2. So v^2 is proportional to r^4, and r x r^4 = r^5.

Does the kinetic energy of the ball increase at terminal velocity?

No. At terminal velocity the speed is constant, so kinetic energy stays fixed. The work done by gravity is fully converted into heat in the liquid.

Is rate of heat the same as energy or power?

It is power (energy per second), measured in watts. Total heat would be power multiplied by time.

What force causes the heating?

The viscous drag force, which is the internal friction between the liquid layers dragged by the moving sphere. This is described by Stokes' law, F = 6 pi eta r v.