What is Relative Velocity in One Dimension?

Physics · Motion In A Straight Line · NEET

Relative velocity of object A with respect to object B is how fast A appears to move when you sit on B and treat B as still. In one dimension the formula is v_AB = v_A - v_B, where both velocities carry a + or - sign for their direction. Memory hook: "Mine minus yours" - your velocity relative to something is always your velocity minus its velocity.
Relative velocity in 1D: v_AB = v_A - v_B+xoriginAv_A = +8 m/sBv_B = +3 m/sFrame of B (B is at rest):Bv_B = 0Av_AB = 8 - 3 = +5 m/sSame direction: subtract. A gains on B at 5 m/s.
In one dimension, sit on object B and treat it as still. A's velocity in that frame is v_AB = v_A - v_B. Here both move in the +x direction, so we subtract: 8 - 3 = 5 m/s, meaning A gains 5 m every second on B.

Your doubts, answered

Is relative velocity just the difference of the two speeds?

No. It is the difference of the two velocities, and velocity carries a sign for direction. First fix a positive direction, then write v_A and v_B with their correct signs, and only then compute v_AB = v_A - v_B. If you subtract raw speeds without signs you will get the wrong answer whenever the two objects move in opposite directions.

Why do we subtract velocities instead of adding them?

The formula v_AB = v_A - v_B always subtracts. The subtraction itself handles both cases through the signs. If B moves opposite to A, then v_B is negative, and subtracting a negative number adds the magnitudes. So you never switch to a plus sign by hand; you just plug in the signed values and let the subtraction do the work.

What does 'with respect to' (w.r.t.) actually mean?

'Velocity of A with respect to B' means: imagine you are standing on B and B feels stationary to you. How fast does A seem to move now? That apparent value is v_AB. The object after 'with respect to' is the one you pretend is at rest, and you subtract its velocity from everything.

Can relative velocity be zero even when both objects are moving?

Yes. If two cars both move at 60 km/h in the same direction, then v_AB = 60 - 60 = 0. To each driver the other car appears frozen in place, staying the same distance away. This zero relative velocity is why cars moving together on a highway seem still to each other.

Is v_AB the same as v_BA?

They are equal in size but opposite in sign: v_AB = -v_BA. If A moves at +5 m/s relative to B, then B moves at -5 m/s relative to A. Always read the subscripts carefully in NEET questions, because they decide the sign of your final answer.

⚠️ The NEET trap
Plugging in speeds as plain positive numbers, so two objects approaching each other at 20 m/s and 15 m/s give a relative velocity of 20 - 15 = 5 m/s.
Assign signs first. If they move opposite ways, one velocity is negative: v_AB = 20 - (-15) = 35 m/s. The closing speed is the sum of magnitudes for opposite directions and the difference for the same direction.
🧠 The number-one NEET mistake in 1D relative velocity is ignoring signs.

Real NEET questions

NEET 2025

Buses leave cities X and Y in both directions at regular intervals of T minutes with the same speed. A girl driving from X to Y at 60 km/h notices that a bus moving in her direction passes her every 30 min, while a bus moving in the opposite direction passes her every 10 min. The interval T and the speed of the buses are respectively:

A · 20 min, 90 km/h
B · 15 min, 120 km/h
C · 10 min, 60 km/h
D · 30 min, 80 km/h
Solution: Let the bus speed be V_b and the fixed spacing between consecutive buses be d = V_b x T. For same-direction buses, the girl catches up on them at the relative speed (V_b - 60), and one passes every 30 min = 1/2 h, so d = (V_b - 60) x (1/2). For opposite-direction buses, the closing relative speed is (V_b + 60), and one passes every 10 min = 1/6 h, so d = (V_b + 60) x (1/6). Setting the two expressions for d equal: (V_b - 60)/2 = (V_b + 60)/6, which gives 3(V_b - 60) = (V_b + 60), so 3V_b - 180 = V_b + 60, giving 2V_b = 240 and V_b = 120 km/h. Then d = (120 - 60) x (1/2) = 30 km, so T = d / V_b = 30/120 h = 1/4 h = 15 min. Answer: 15 min, 120 km/h (option B).

Solved Motion In A Straight Line NEET PYQs

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Frequently asked

What is the formula for relative velocity in one dimension?

The velocity of A with respect to B is v_AB = v_A - v_B, where v_A and v_B are the signed velocities measured in the same reference frame along the same line.

Is relative velocity a scalar or a vector?

It is a vector. In one dimension the direction is shown by the + or - sign, so v_AB has both a magnitude and a direction along the chosen axis.

How is relative velocity different for same and opposite directions?

For the same direction you subtract the magnitudes, and for opposite directions you add them. Both cases come out automatically from v_AB = v_A - v_B once you put in the correct signs.

Why is relative velocity important for NEET?

Many NEET kinematics problems (trains crossing, buses passing, boats, lifts) are solved fastest by shifting to the frame of one object using relative velocity, which turns a two-body problem into a simple one-body problem.

What does zero relative velocity mean physically?

It means the two objects keep a constant separation; each one sees the other as stationary. This happens when both move with equal velocities in the same direction.