Maximum Velocity and Maximum Acceleration in SHM

Physics · Oscillations · NEET

In SHM the maximum velocity is v_max = A*w (A = amplitude, w = angular frequency). It happens at the mean position (x = 0), where speed is highest and acceleration is zero. The maximum acceleration is a_max = A*w^2, and it happens at the extreme positions (x = +A or x = -A), where the body stops for an instant. Memory hook: at the middle you MOVE fastest, at the ends you PULL hardest.
x = -Ax = +Ax = 0 (mean)v_max = A*wa = 0v = 0a_max = A*w^2v = 0a_max = A*w^2Extreme: fastest pullMean: fastest speed
In SHM, velocity is maximum (A*w) at the mean position where acceleration is zero, while acceleration is maximum (A*w^2) at the two extreme positions where velocity is zero.

Your doubts, answered

Where exactly is velocity maximum and where is it zero?

Velocity is maximum at the mean position (x = 0), the centre of the motion. Here v_max = A*w. Velocity becomes zero at the extreme positions (x = +A and x = -A), because the body stops for a moment before turning back. Use v = w*root(A^2 - x^2): put x = 0 to get the biggest value, put x = A to get zero.

Where is acceleration maximum and where is it zero?

Acceleration is maximum at the extreme positions (x = +A or x = -A), where a_max = A*w^2. It is zero at the mean position (x = 0). This is the opposite of velocity. Use a = -w^2*x: bigger x means bigger acceleration, and x = 0 gives zero acceleration.

Why are v_max and a_max at opposite places?

Velocity depends on how far the body is from the centre through v = w*root(A^2 - x^2), so it is largest at the centre. Acceleration depends directly on displacement through a = -w^2*x, so it is largest at the ends. That is why the body moves fastest in the middle but feels the strongest pull-back force at the ends.

How do I remember v_max = Aw and a_max = Aw^2?

Both start with amplitude A. Velocity has one power of w (v_max = A*w) and acceleration has two powers of w (a_max = A*w^2). Each time you go from displacement to velocity to acceleration you multiply by one more w. So displacement max = A, velocity max = A*w, acceleration max = A*w^2.

What is the ratio a_max / v_max?

Divide a_max by v_max: (A*w^2) / (A*w) = w. So a_max / v_max = w (angular frequency). This is a quick shortcut in NEET numericals: if a question gives you both maximum values, w is simply their ratio.

⚠️ The NEET trap
Acceleration is maximum at the mean position because that is where the body is fastest.
Acceleration is maximum at the EXTREME position (a_max = A*w^2). At the mean position acceleration is ZERO. Fast speed and high acceleration do not happen at the same place in SHM.
🧠 Fastest and strongest are at opposite ends: v_max at the middle, a_max at the edges.

Real NEET questions

2017

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity equals the magnitude of its acceleration. Its time period (in seconds) is

A · 5/(2*pi)
B · (5*root2)/pi
C · (4*pi)/root5
D · (2*pi)/root3
Solution: Use v = w*root(A^2 - x^2) and a = w^2*x. Set them equal: w*root(A^2 - x^2) = w^2*x, so root(A^2 - x^2) = w*x. Then w = root(A^2 - x^2)/x. With A = 3 cm and x = 2 cm: w = root(9 - 4)/2 = root5/2 rad/s. Time period T = 2*pi/w = 2*pi*(2/root5) = 4*pi/root5 s.
2025

Two identical point masses P and Q, suspended from two separate massless springs of spring constants k1 and k2, oscillate vertically. If their maximum speeds are the same, the ratio A_Q/A_P of the amplitude of mass Q to that of mass P is

A · root(k2/k1)
B · root(k1/k2)
C · k2/k1
D · k1/k2
Solution: Maximum speed in SHM is v_max = A*w, and for a spring w = root(k/m). So v_max = A*root(k/m). The masses are identical (m_P = m_Q = m) and their v_max is the same: A_P*root(k1/m) = A_Q*root(k2/m). Cancel m: A_P*root(k1) = A_Q*root(k2). Therefore A_Q/A_P = root(k1/k2).

Solved Oscillations NEET PYQs

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Frequently asked

What is the formula for maximum velocity in SHM?

v_max = A*w, where A is amplitude and w is angular frequency. It occurs at the mean position (x = 0).

What is the formula for maximum acceleration in SHM?

a_max = A*w^2, where A is amplitude and w is angular frequency. It occurs at the extreme positions (x = +A or x = -A).

At the mean position, what are the values of velocity and acceleration?

At the mean position velocity is maximum (A*w) and acceleration is zero. The body moves fastest here but feels no restoring force.

At the extreme position, what are the values of velocity and acceleration?

At the extreme position velocity is zero and acceleration is maximum (A*w^2). The body stops for an instant and feels the strongest pull back toward the centre.

How is w found from a_max and v_max?

Divide them: w = a_max / v_max. Since a_max = A*w^2 and v_max = A*w, the amplitude cancels and you are left with w.