What Is a Light Emitting Diode (LED)? Working Explained

Physics · Semiconductor Electronics : Materials, Devices And Simple Circuits · NEET

A Light Emitting Diode (LED) is a heavily doped p-n junction diode that gives out light when it is forward biased. When electrons and holes cross the junction and recombine, the energy released comes out as light (this is called electroluminescence). Memory hook: LED = "Light when Electrons Drop" into holes; and it only shines in forward bias, never reverse bias.

At a glance

Bias needed to emit lightLED: forward bias onlyPhotodiode: reverse bias for operation
Energy conversionLED: electrical energy to lightOrdinary diode: energy mostly to heat
MaterialLED: GaAs, GaAsP, GaPOrdinary diode: Si, Ge
Turn-on voltageLED: about 1.8 to 3 VSilicon diode: about 0.7 V
LED: Forward Biased p-n Junction Emitting Lightpnjunctionhole +electron -lightrecombination gives photon: E(photon) = Eg = hc / lambda+-Key factsForward bias onlyColour set by EgNeeds ~1.8 to 3 V
In forward bias, electrons from the n-side and holes from the p-side move to the junction and recombine. Each recombination releases a photon of energy equal to the band gap Eg, giving light whose colour depends on Eg through E = hc/lambda.

Your doubts, answered

Does an LED emit light in reverse bias?

No. An LED emits light only in forward bias. In forward bias, electrons and holes are pushed toward the junction, they recombine, and release energy as light. In reverse bias almost no current flows, so there is no recombination and no light. Also, LEDs have a very low reverse breakdown voltage (around 5 V), so reverse bias can even damage them.

Why does an LED give light but an ordinary silicon diode does not?

Both are p-n junctions and both have recombination. The difference is the material. Ordinary silicon and germanium diodes release the recombination energy mostly as heat (their band structure favours heat). LEDs are made from special compound semiconductors like GaAs, GaAsP and GaP, which release the energy as photons of visible or infrared light. So the material band structure, not the diode idea, decides whether you get light.

What decides the colour of light emitted by an LED?

The colour depends on the energy gap (Eg) of the semiconductor. The photon energy of the emitted light is roughly equal to Eg, and photon energy is E = hc/lambda. A larger Eg gives shorter wavelength (toward blue/violet); a smaller Eg gives longer wavelength (toward red/infrared). So by choosing a material with the right Eg, we choose the colour.

Why does an LED need a higher voltage than a silicon diode?

To emit visible light the photon energy (and so Eg) must be about 1.8 eV or more. Since the turn-on voltage roughly matches this energy, an LED typically needs about 1.8 V to 3 V, higher than the 0.7 V of silicon. A resistor is always put in series with an LED to limit the current, otherwise the current becomes too large and burns the LED.

What is electroluminescence in the context of an LED?

Electroluminescence means giving out light because of an electric current, not because of heat. In an LED, forward current drives electrons and holes to the junction where they recombine. Each recombination releases energy equal to the band gap as a photon of light. This direct conversion of electrical energy into light is electroluminescence.

⚠️ The NEET trap
An LED works in reverse bias because it is a special diode, and its colour depends on the applied voltage.
An LED works only in forward bias, and its colour depends on the energy gap (Eg) of the semiconductor, not on the applied voltage. Photon energy is about equal to Eg, and E = hc/lambda fixes the wavelength.
🧠 NTA loves swapping forward with reverse for LEDs, and swapping 'energy gap' with 'applied voltage' for the colour. Lock in: LED shines in FORWARD bias only, and COLOUR comes from Eg.

Real NEET questions

2019

An LED is constructed from a p-n junction diode using GaAsP. The energy gap is 1.9 eV. The wavelength of the light emitted will be equal to:

A · 10.4 x 10^-26 m
B · 654 nm
C · 654 A
D · 654 x 10^-11 m
Solution: Step 1: The photon energy equals the band gap, so E = 1.9 eV. Step 2: Use lambda = hc/E. A fast shortcut is lambda (in Angstrom) = 12400 / E(in eV). Step 3: lambda = 12400 / 1.9 = 6526 A (approximately). Step 4: Convert to nm: 6526 A = 652.6 nm, which is about 654 nm. So the answer is 654 nm (option B). Note options C and D give the wrong power of ten, and option A is off by a huge factor.

Solved Semiconductor Electronics : Materials, Devices And Simple Circuits NEET PYQs

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Frequently asked

What is an LED in simple words?

An LED is a light emitting diode: a p-n junction that turns electrical energy directly into light when it is forward biased. The light comes from electrons and holes recombining at the junction.

In which bias does an LED work?

Only in forward bias. Forward current causes recombination that releases photons. In reverse bias there is no current and no light, and reverse bias can damage the LED.

Which materials are used to make LEDs?

Compound semiconductors such as gallium arsenide (GaAs), gallium arsenide phosphide (GaAsP) and gallium phosphide (GaP). Their energy gap is chosen to get the desired colour.

How is the colour of an LED related to its energy gap?

The emitted photon energy is about equal to the energy gap Eg. Using E = hc/lambda, a larger Eg gives shorter wavelength (blue side) and a smaller Eg gives longer wavelength (red or infrared).

Why is a resistor connected in series with an LED?

To limit the current. Once the LED turns on, its resistance is very low, so without a series resistor the current would rise too high and destroy the LED.