Linear Expansion and Coefficient of Linear Expansion (alpha)

Physics · Thermal Properties Of Matter · NEET

When a solid rod is heated, its length increases. The extra length is delta L = L alpha delta T, where L is the original length, delta T is the rise in temperature, and alpha is the coefficient of linear expansion. So alpha = delta L / (L delta T) tells you the fractional increase in length for each 1 degree rise. Memory hook: alpha is "how much a 1 metre rod stretches per 1 degree." Its SI unit is per kelvin (K^-1), and for metals alpha is tiny, about 10^-5 K^-1.
Linear Expansion of a Rod on HeatingOriginal rod, length L (cold)LHeated rod, new length L + delta L (hot)delta Ldelta L = L alpha delta Talpha = delta L / (L delta T)unit of alpha: K^-1
A rod of original length L expands by delta L = L alpha delta T when its temperature rises by delta T. The coefficient alpha (unit K^-1) is the fractional increase in length per degree, so longer rods and hotter rises give larger delta L.

Your doubts, answered

Does delta L depend on the original length of the rod?

Yes. From delta L = L alpha delta T, a longer rod expands more for the same temperature rise. A 2 metre rod stretches twice as much as a 1 metre rod of the same material. But alpha itself does not depend on length; alpha is a material property. Only the actual increase delta L scales with L.

What is the SI unit of the coefficient of linear expansion alpha?

From alpha = delta L / (L delta T), delta L and L are both lengths (metre), so they cancel. What is left is 1 / temperature. So the SI unit is per kelvin, written K^-1 (same as per degree Celsius, since a 1 K change equals a 1 degree C change). Alpha has no length unit.

If a metal plate has a hole, does the hole get bigger or smaller on heating?

The hole gets BIGGER. Every part of the metal expands outward together, as if the hole were filled with the same metal. So a hole, a gap, or a cavity expands just like solid metal. This is why a blacksmith heats an iron ring to slip it onto a wheel: the inner hole grows.

What is the difference between delta L and alpha?

delta L is the actual increase in length in metres, and it changes with the rod length and the temperature rise. Alpha is a fixed number for a given material (like 1.7 x 10^-5 K^-1 for copper) that measures how strongly that material expands. Alpha is the cause; delta L is the result you measure.

Why is alpha so small, around 10^-5, for solids?

In a solid the atoms are held tightly by strong bonds and only vibrate a little more when heated. So the spacing between atoms grows by only a tiny fraction per degree. That is why a 1 metre steel rod grows only about 0.011 mm per degree. Gases have no such bonds, so gases expand far more than solids.

⚠️ The NEET trap
Thinking alpha itself changes if you take a longer rod, or forgetting that delta L is proportional to the original length L.
Alpha is a material constant and does not change with length. Only the actual expansion delta L = L alpha delta T grows with length. Two rods of the SAME material but different lengths have the SAME alpha but DIFFERENT delta L for the same delta T.
🧠 Alpha belongs to the material, delta L belongs to the rod.

Real NEET questions

NEET 2019

A copper rod of length 88 cm and an aluminium rod of unknown length have their increase in length independent of the increase in temperature. The length of the aluminium rod is: (alpha_Cu = 1.7 x 10^-5 K^-1, alpha_Al = 2.2 x 10^-5 K^-1)

A · 6.8 cm
B · 113.9 cm
C · 88 cm
D · 68 cm
Solution: For the difference in lengths to stay the same at all temperatures, both rods must expand by the same amount. So delta L (copper) = delta L (aluminium). Using delta L = L alpha delta T for the same delta T: L_Cu x alpha_Cu = L_Al x alpha_Al. Then L_Al = L_Cu x alpha_Cu / alpha_Al = 88 x (1.7 x 10^-5) / (2.2 x 10^-5) = 88 x 0.7727 = 68 cm. So the aluminium rod is 68 cm long, option D.

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Frequently asked

What is the formula for linear expansion?

delta L = L alpha delta T, where delta L is the increase in length, L is the original length, alpha is the coefficient of linear expansion, and delta T is the temperature rise. The new length is L' = L (1 + alpha delta T).

What does the coefficient of linear expansion alpha mean?

Alpha is the fractional increase in length of a material per 1 degree rise in temperature. If alpha = 1.7 x 10^-5 K^-1 for copper, then each metre of copper grows by 1.7 x 10^-5 metre for every 1 degree of heating.

What is the SI unit of alpha?

Per kelvin, written K^-1. It is the same numerically as per degree Celsius because a change of 1 kelvin equals a change of 1 degree Celsius.

Does alpha depend on temperature?

For small temperature changes we treat alpha as a constant. Over very large temperature ranges alpha varies slightly, but for NEET problems you use a fixed value.

How is alpha related to the area and volume coefficients?

For an isotropic solid, the area expansion coefficient beta = 2 alpha and the volume expansion coefficient gamma = 3 alpha. So alpha : beta : gamma = 1 : 2 : 3.