Specific Heat Capacity of Gases: Cp and Cv Explained

Physics · Thermodynamics · NEET

A gas has two molar specific heats: Cv is the heat needed to raise 1 mole by 1 K at constant volume, and Cp is the heat needed at constant pressure. Cp is always larger because at constant pressure the gas also does work while expanding, so extra heat is needed. Memory hook: "P is bigger because the gas pushes" - Cp pays for both heating and pushing, Cv pays only for heating.
Two ways to heat 1 mole of gas by 1 KConstant Volume (Cv)piston fixedno work doneQ = Cv = heat onlyConstant Pressure (Cp)piston movesQ = Cp = heat + workCp - Cv = R (extra heat = work done)
At constant volume all heat raises temperature (Cv), but at constant pressure the gas also pushes the piston and does work, so it needs more heat (Cp). The extra amount is exactly R, giving Mayer's relation Cp - Cv = R.

Your doubts, answered

Why does a gas need two specific heats when a solid needs only one?

A gas can be heated in two very different ways. If you keep the volume fixed, all the heat goes into raising temperature (internal energy), so you use Cv. If you keep the pressure fixed, the gas expands and pushes the piston, so some heat is spent doing work and less is left to raise temperature; you need more heat, so you use Cp. Solids and liquids barely expand, so their two values are almost equal and we usually quote one number. Gases expand a lot, so Cp and Cv are clearly different.

What is the difference between specific heat capacity (s) and molar specific heat capacity (C)?

Specific heat capacity s is heat per unit mass per kelvin, unit J per kg per K. Molar specific heat capacity C is heat per mole per kelvin, unit J per mol per K. For gases NEET almost always uses the molar form, written Cp and Cv, because gas amounts are counted in moles (n). The relation Cp - Cv = R only works for the molar versions, since R is a per-mole constant.

Why is Cv equal to the change in internal energy per degree?

At constant volume the gas does no work (W = P times change in V = 0). By the first law Q = change in U + W, so Q = change in U. Dividing by the temperature change for 1 mole gives Cv = change in U divided by change in T. This is why Cv is the natural link between heat and internal energy, and why for any process the change in internal energy of an ideal gas is n Cv times change in T, even when the volume is not constant.

How do I remember the values of Cp and Cv for monatomic and diatomic gases?

Start from Cv, which comes from degrees of freedom f: Cv = (f/2) R. Monatomic gas (like He, Ar) has f = 3, so Cv = 3/2 R and Cp = 5/2 R. Diatomic gas (like O2, N2) has f = 5 at NEET level, so Cv = 5/2 R and Cp = 7/2 R. Always add R to Cv to get Cp because Cp - Cv = R. Do not mix these up: the bigger number is always Cp.

⚠️ The NEET trap
Using Cp to find the change in internal energy, or using Cv to find heat in an isobaric (constant pressure) process.
Change in internal energy of an ideal gas is always n Cv times change in T for ANY process. Heat depends on the process: at constant volume Q = n Cv dT, at constant pressure Q = n Cp dT.
🧠 Internal energy always rides on Cv; only the heat label switches between Cv and Cp depending on the process.

Real NEET questions

2018

The volume (V) of a monatomic gas varies with its temperature (T) as a straight line through the origin, from A to B (an isobaric process). The ratio of the work done by the gas to the heat absorbed by it, when it goes from A to B, is

A · 1/3
B · 2/3
C · 2/5
D · 2/7
Solution: Since V is proportional to T (straight line through origin), V/T is constant, so pressure P is constant. The process is isobaric. Work done W = P times change in V = nR times change in T. Heat absorbed at constant pressure Q = n Cp times change in T. So W/Q = R/Cp. For a monatomic gas Cp = 5/2 R. Therefore W/Q = R divided by (5/2 R) = 2/5. Correct option is C.

Solved Thermodynamics NEET PYQs

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Frequently asked

What is Mayer's relation?

Mayer's relation states Cp - Cv = R for one mole of an ideal gas, where R is the universal gas constant (about 8.31 J per mol per K). It shows the extra heat needed at constant pressure equals the work done during expansion for a 1 K rise.

Can Cp ever be equal to or less than Cv?

No. For an ideal gas Cp is always greater than Cv by exactly R. Cp equals Cv only in the imaginary case where the gas cannot do work, which does not happen for real gases that expand.

What is the ratio Cp/Cv called?

The ratio Cp/Cv is called gamma, the ratio of specific heats or adiabatic index. It is 5/3 (about 1.67) for monatomic gases and 7/5 (1.4) for diatomic gases, and appears in the adiabatic equation P V^gamma = constant.

Which specific heat do I use to find the change in internal energy?

Always use Cv. For an ideal gas the change in internal energy is n Cv times the change in temperature for every process, including isobaric and adiabatic, because internal energy depends only on temperature.

Why is molar specific heat used for gases instead of per kg?

Gas amounts are counted in moles, and equal moles of any ideal gas behave similarly. The per-mole form lets Mayer's relation Cp - Cv = R stay simple, since R is defined per mole.