Conservation of Mechanical Energy: Statement and Proof

Physics · Work, Energy And Power · NEET

The law of conservation of mechanical energy says that when only conservative forces (like gravity or a spring) act on a body, the total mechanical energy E = KE + PE stays constant. Energy just changes form: potential energy turns into kinetic energy and back, but the sum never changes. Memory hook: "PE + KE = same number, always" as long as there is no friction or air drag to steal energy.
Free Fall: KE + PE = constanttopgroundmPE = mgh (max)KE = 0PE fallsKE risesPE = 0KE = (1/2)mv^2 (max)At every levelmgh + (1/2)mv^2= constant = mgH(only gravity acts,no friction)
As a body falls freely, its potential energy (mgh) converts into kinetic energy ((1/2)mv^2). At every height the sum KE + PE equals the starting energy mgH, because gravity is a conservative force and no friction acts.

Your doubts, answered

When exactly is mechanical energy conserved, and when is it not?

Mechanical energy (KE + PE) is conserved only when the net work done by non-conservative forces is zero. In practice this means no friction, no air drag, and no external push or pull removing energy. Gravity and spring force are conservative, so a ball in free fall or a block on a frictionless track keeps E constant. The moment friction or air resistance acts, some mechanical energy turns into heat, so KE + PE goes down.

If friction is present, is energy still conserved?

Total energy is always conserved, but mechanical energy is not. With friction, mechanical energy (KE + PE) decreases because part of it becomes heat and sound. So you must write: initial mechanical energy = final mechanical energy + energy lost to friction. For NEET, if a question mentions a 'rough' surface or 'air resistance', do not set KE + PE constant.

How do you prove conservation of mechanical energy?

Take a body under only a conservative force F. The work-energy theorem gives W = change in KE. For a conservative force, the same work equals the drop in potential energy: W = -(change in PE). Setting them equal: change in KE = -(change in PE), so change in KE + change in PE = 0, which means KE + PE = constant. That constant total is the conserved mechanical energy.

What is the difference between conservation of energy and conservation of mechanical energy?

Conservation of total energy is a universal law: energy is never created or destroyed, it only changes form (heat, light, sound, mechanical). Conservation of mechanical energy is a special, narrower case that holds only when non-conservative forces do no work. Mechanical energy can 'disappear' as heat, but total energy is still conserved.

Why does KE + PE stay constant in free fall?

In free fall the only force is gravity, a conservative force. As the body falls, height h decreases so PE = mgh falls, and speed increases so KE = (1/2)mv^2 rises by exactly the same amount. At every point mgh + (1/2)mv^2 gives the same total, equal to the initial energy at release.

⚠️ The NEET trap
Applying KE + PE = constant on a rough surface or when air resistance is mentioned.
Use conservation of mechanical energy ONLY when forces are conservative (frictionless, no drag). If friction acts, write initial ME = final ME + heat lost.
🧠 See the words 'rough', 'friction', or 'air resistance'? Mechanical energy is NOT conserved. See 'smooth', 'frictionless', or 'free fall'? It IS conserved.

Real NEET questions

NEET 2021

A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of the Earth and the speed of the particle at that instant are respectively

A · 3S/4, sqrt(3gS/2)
B · S/4, sqrt(3gS/2)
C · S/4, 3gS/2
D · 3S/4, 3gS/2
Solution: Take PE = 0 at the ground. At release (height S, at rest) total mechanical energy E = mgS. Only gravity acts, so E is conserved. At height h: PE = mgh and KE = 3 x PE = 3mgh. Total: KE + PE = 3mgh + mgh = 4mgh = mgS, so h = S/4. Now KE = 3mgh = 3mg(S/4) = (1/2)mv^2. Cancel m: v^2 = 6g(S/4)/1 = 3gS/2, so v = sqrt(3gS/2). Answer: h = S/4 and v = sqrt(3gS/2).
NEET 2026

The sum of the kinetic energy and potential energy of a simple pendulum bob is 0.02 J. The speed of the bob at the equilibrium position is approximately (mass of the bob = 20 g)

A · 0.2 m/s
B · 1.41 m/s
C · 14.1 m/s
D · 2.0 m/s
Solution: For a swinging pendulum only gravity and string tension act. Tension does no work (always perpendicular to motion), so mechanical energy is conserved: KE + PE = 0.02 J everywhere. At the lowest (equilibrium) point the bob is at its lowest height, so PE = 0 and all energy is kinetic: (1/2)mv^2 = 0.02 J. With m = 20 g = 0.02 kg: v^2 = 2(0.02)/0.02 = 2, so v = sqrt(2) = 1.41 m/s.

Solved Work, Energy And Power NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

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Frequently asked

State the law of conservation of mechanical energy.

When the only forces doing work on a system are conservative forces (such as gravity or a spring force), the total mechanical energy E = KE + PE of the system remains constant throughout the motion.

What are the conditions for mechanical energy to be conserved?

Two conditions: (1) only conservative forces do work, and (2) non-conservative forces like friction and air resistance do zero net work. If either fails, mechanical energy is not conserved.

Is tension a conservative or non-conservative force in a pendulum?

String tension in a pendulum does no work because it is always perpendicular to the bob's velocity. Since it does zero work, it does not change mechanical energy, so KE + PE stays constant during the swing.

Does conservation of mechanical energy break the law of conservation of energy?

No. When friction lowers mechanical energy, that energy becomes heat and sound. Total energy is still conserved; only its mechanical form has decreased.

Why is conservation of mechanical energy important for NEET?

It is the fastest way to solve problems on free fall, pendulums, vertical circles, inclined planes and springs without using force and acceleration. NEET regularly tests it as a one-line equation: initial (KE + PE) = final (KE + PE).