Gravitational Potential Energy: Formula mgh

Physics · Work, Energy And Power · NEET

Gravitational potential energy is the energy a body stores because of its height above a chosen reference level. The formula is PE = mgh, where m is mass (kg), g is 9.8 m/s^2 (often 10 in NEET), and h is height (m); the unit is the joule (J). Memory hook: "mgh — mass goes higher, energy gets higher."
Reference level h = 0 (ground)mhPE = mgh (all stored)g (falls)mKE = 1/2 mv^2 (all motion)vFree fall: mgh converts to 1/2 mv^2, total energy constant
A mass at height h stores gravitational potential energy mgh. As it falls, this PE converts into kinetic energy 1/2 mv^2 while the total mechanical energy stays constant. Height h is always measured vertically from the chosen reference level.

Your doubts, answered

Where does the formula PE = mgh come from?

To lift a body of mass m slowly through a height h, you apply an upward force equal to its weight mg. Work done against gravity = force x displacement = mg x h = mgh. This work does not vanish; it gets stored in the body as gravitational potential energy. So PE = mgh. NCERT derives it by noting that when the body is released, this stored mgh reappears exactly as kinetic energy 1/2 mv^2 on reaching the ground.

Why do we use height h and not the actual distance travelled?

Gravity acts only vertically (downward). Work by gravity depends only on the vertical drop or rise, never on the horizontal path. If a body slides down a curved ramp or a straight incline of the same height h, the change in gravitational PE is mgh in both cases. This is why gravity is a conservative force. For NEET, always take h as the vertical height, not the length of the slope.

Does it matter where I put h = 0?

The value of mgh is not absolute; it depends on where you set the reference level (h = 0). You can put h = 0 at the ground, at a table top, or anywhere convenient. Only the CHANGE in potential energy, mg(h2 - h1), has physical meaning and is the same no matter which reference you pick. In NEET problems, choose the reference that makes the numbers simple, usually the lowest point of the motion.

How is mgh different from kinetic energy 1/2 mv^2?

PE = mgh is stored energy due to position (height). KE = 1/2 mv^2 is energy of motion (speed). During free fall PE keeps converting into KE while their sum (mechanical energy) stays constant. At the top: all PE, zero KE. At the bottom: all KE, zero PE. Both are measured in joules.

Can gravitational potential energy be negative?

With the simple mgh formula, PE is negative when the body is below your chosen h = 0 level (h is negative). This is normal and just reflects your reference choice. Separately, in gravitation using the exact formula -GMm/r, PE is always negative because the zero is fixed at infinity. For the Work-Energy-Power chapter, stick to mgh and let the sign of h follow your reference.

⚠️ The NEET trap
For a block sliding down a 5 m long incline inclined at 30 degrees, students plug h = 5 m into mgh.
The vertical height is h = 5 sin30 = 2.5 m, so PE lost = mg(2.5). Gravity only cares about vertical drop; the extra slope length is horizontal-ish travel that gravity does no work along. Always resolve to the true vertical height.
🧠 When a body slides down an incline, use vertical height, not slope length.

Real NEET questions

NEET 2021

A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of the Earth and the speed of the particle at that instant are respectively

A · 3S/4, sqrt(3gS/2)
B · S/4, sqrt(3gS/2)
C · S/4, 3gS/2
D · 3S/4, 3gS/2
Solution: Step 1 (total energy): At release the particle is at rest at height S, so total mechanical energy = PE = mgS. Step 2 (use KE = 3 PE): At the height h in question, KE = 3(PE). Total energy = KE + PE = 3PE + PE = 4PE = 4(mgh). Step 3 (equate and solve h): 4mgh = mgS gives h = S/4. So the particle is at height S/4 above the ground. Step 4 (find speed): KE = 3 PE = 3 mg(S/4) = (3/4)mgS. Also KE = 1/2 mv^2, so 1/2 mv^2 = (3/4)mgS. Cancel m: v^2 = (3/2)gS, giving v = sqrt(3gS/2). Answer: height = S/4, speed = sqrt(3gS/2), option B.
NEET 2026

The sum of the kinetic energy and potential energy of a simple pendulum bob is 0.02 J. The speed of the bob at the equilibrium position is approximately (mass of the bob = 20 g)

A · 0.2 m/s
B · 1.41 m/s
C · 14.1 m/s
D · 2.0 m/s
Solution: Step 1 (idea): Total mechanical energy KE + PE stays constant = 0.02 J. At the equilibrium (lowest) position the height is minimum, so gravitational PE = 0 and all energy is kinetic. Step 2 (set KE = total): 1/2 mv^2 = 0.02 J, with m = 20 g = 0.02 kg. Step 3 (solve): v^2 = (2 x 0.02) / 0.02 = 2, so v = sqrt(2) = 1.41 m/s. Answer: 1.41 m/s, option B.

Solved Work, Energy And Power NEET PYQs

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Frequently asked

What is the formula for gravitational potential energy?

PE = mgh, where m is mass in kg, g is acceleration due to gravity (9.8 m/s^2, often taken as 10 in NEET), and h is the vertical height above the reference level. The unit is the joule (J).

What is the SI unit and dimension of gravitational potential energy?

The SI unit is the joule (J). Its dimensional formula is [M L^2 T^-2], the same as all forms of energy and work.

Is gravitational potential energy a scalar or vector?

It is a scalar. It has only magnitude (and a sign that depends on the reference level), no direction.

What is the value of g used in NEET numericals?

Read the question. If g is given as 10 m/s^2, use 10; otherwise use 9.8 m/s^2. Most NEET problems state g = 10 m/s^2 to keep arithmetic clean.

Why is gravitational PE called stored energy?

Work done in lifting a body against gravity is not lost; it is stored by virtue of the body's raised position. When released, this stored energy converts fully into kinetic energy, showing it was truly stored.