ReNEET 2026 · Chemistry · Q72Amines / Haloalkanes (Grignard)In our bank: Strong match · 90%

One of the products formed in the following reaction is: cyclohexyl–MgBr + cyclohexyl–NH₂→

ReNEET 2026 Chemistry Question 72 figure
  1. A.a dicyclohexylamine ((C₆H₁₁)₂NH)
  2. B.a substituted amine bearing NH₂
  3. C.bicyclohexyl (C₆H₁₁-C₆H₁₁)
  4. D.cyclohexane (C₆H₁₂)

Correct Answer

(D) cyclohexane (C₆H₁₂)

Solution & Explanation

A Grignard reagent (R–MgBr) carries a strongly nucleophilic, strongly BASIC carbanion-like carbon, R⁻. Before it can add to anything, it reacts with any acidic proton present. Cyclohexylamine, C₆H₁₁–NH₂, has acidic N–H protons. The cyclohexyl carbanion of the Grignard simply abstracts an N–H proton (acid–base reaction), so it is protonated and converted to the hydrocarbon: C₆H₁₁–MgBr + C₆H₁₁–NH₂ → C₆H₁₂ (cyclohexane) + C₆H₁₁–NH–MgBr (magnesium amide salt). No C–C or C–N bond forms; the reaction stops at simple protonation because the N–H proton is consumed first. Trap: do not expect coupling (bicyclohexyl) or amine substitution — the basic destruction of the reagent dominates. Answer: cyclohexane (option D).

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