Axial vs Equatorial Bonds in PCl5: Why Axial Bonds Are Longer

Chemistry · Chemical Bonding · NEET

PCl5 has a trigonal bipyramidal shape. Its 5 P-Cl bonds are not all equal: the 2 axial bonds (top and bottom) are LONGER and weaker than the 3 equatorial bonds (in the middle plane). This happens because each axial bond faces more electron repulsion (3 close bonds at 90 degrees) than an equatorial bond (only 2 close bonds at 90 degrees). Memory hook: "Axial = Above and below = more crowded = longer."
PCl5 - Trigonal Bipyramidal (sp3d)PClClClClClAxial: 2 bonds, LONGER (~219 pm)3 neighbours at 90 = more repulsionEquatorial: 3 bonds, shorter (~204 pm)2 neighbours at 90 = less repulsionAngles: eq-eq 120, ax-eq 90, ax-ax 180Longer = weaker -> PCl5 is reactive
In PCl5 the 3 green equatorial bonds sit in one plane (120 degrees apart) while the 2 red axial bonds point up and down. Axial bonds face 3 neighbours at 90 degrees versus only 2 for equatorial, so axial bonds are longer and weaker - which is why PCl5 is reactive.

Your doubts, answered

What is the difference between axial and equatorial bonds in PCl5?

PCl5 is trigonal bipyramidal (sp3d). Three P-Cl bonds lie in one flat middle plane and point 120 degrees apart. These are the EQUATORIAL bonds. The other two P-Cl bonds point straight up and straight down (perpendicular to that plane, 180 degrees apart). These are the AXIAL bonds. So: 3 equatorial + 2 axial = 5 bonds in total.

Why are the axial bonds longer than the equatorial bonds in PCl5?

Bond length depends on how much repulsion the bonding electrons feel from nearby bonds. Count the bonds that sit at 90 degrees (the strongest repulsion angle). Each AXIAL bond has 3 neighbours at 90 degrees (the three equatorial bonds). Each EQUATORIAL bond has only 2 neighbours at 90 degrees (the two axial bonds). More 90-degree repulsion pushes the axial atom slightly away, so the axial bond is longer and weaker. Remember: more repulsion = longer, weaker bond.

How many bonds in PCl5 are longer, 2 or 3?

Two bonds are longer. The 2 axial bonds are the longer ones (about 219 pm). The 3 equatorial bonds are shorter (about 204 pm). A common mistake is to say all 5 P-Cl bonds are equal because they are all 'P-Cl'. They are NOT equal in a trigonal bipyramid.

What are the bond angles in PCl5?

There are three angles. Equatorial to equatorial = 120 degrees (in the middle plane). Axial to equatorial = 90 degrees. Axial to axial (top to bottom) = 180 degrees. Because these angles are different, the bonds are not all equivalent, unlike in a symmetric shape such as SF6 (octahedral, all 90 degrees).

Why is PCl5 unstable or reactive?

The two axial bonds are longer and weaker, so they break easily. In the solid, PCl5 even splits into ions. This weakness makes PCl5 a reactive chlorinating agent. So 'PCl5 is non-reactive' is a WRONG statement, which NEET has directly tested.

Is PCl5 polar or non-polar?

PCl5 is non-polar. Even though the axial and equatorial bonds differ in length, the shape is symmetric enough that the bond dipoles cancel out. Its net dipole moment is zero. The same is true for the similar molecules SbCl5 and PF5.

⚠️ The NEET trap
All five P-Cl bonds in PCl5 are equal in length, and PCl5 is a stable, non-reactive molecule.
The 2 axial P-Cl bonds are longer than the 3 equatorial bonds because axial bonds face greater 90-degree repulsion. This weakness makes PCl5 REACTIVE (it acts as a chlorinating agent and even ionises in the solid state).
🧠 NEET 2022 and 2026 both asked this. The trap option is 'PCl5 is non-reactive' - it is FALSE. Longer axial bonds = weaker = reactive.

Real NEET questions

2022

Identify the incorrect statement related to PCl5 from the following:

A · Three equatorial P-Cl bonds make an angle of 120 degrees with each other
B · Two axial P-Cl bonds make an angle of 180 degrees with each other
C · Axial P-Cl bonds are longer than equatorial P-Cl bonds
D · PCl5 molecule is non-reactive
Solution: PCl5 is trigonal bipyramidal (sp3d). Statements A (equatorial angle 120 degrees), B (axial angle 180 degrees) and C (axial bonds longer due to greater repulsion) are all CORRECT. But PCl5 is reactive - it hydrolyses and acts as a chlorinating agent. So the INCORRECT statement is D, 'PCl5 is non-reactive'. (This question reappeared in NEET 2026.)
2021

Match List-I with List-II. List-I: (a) PCl5, (b) SF6, (c) BrF5, (d) BF3. List-II: (i) Square pyramidal, (ii) Trigonal planar, (iii) Octahedral, (iv) Trigonal bipyramidal.

A · (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
B · (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
C · (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
D · (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
Solution: PCl5 (sp3d, AB5) is trigonal bipyramidal (iv) - this is the shape that gives the axial/equatorial split. SF6 (sp3d2, AB6) is octahedral (iii). BrF5 (sp3d2, AB5E) is square pyramidal (i). BF3 (sp2, AB3) is trigonal planar (ii). So the answer is (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii).

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Frequently asked

How long are the axial and equatorial bonds in PCl5?

The axial P-Cl bonds are about 219 pm and the equatorial P-Cl bonds are about 204 pm. So the axial bonds are roughly 15 pm longer. You do not need exact numbers for NEET - just remember axial > equatorial in length.

What is the hybridisation of PCl5?

PCl5 uses sp3d hybridisation. Phosphorus mixes one s, three p and one d orbital to make five sp3d hybrid orbitals that point to the corners of a trigonal bipyramid. Each overlaps with a p orbital of chlorine to form five P-Cl sigma bonds.

Do other trigonal bipyramidal molecules also have longer axial bonds?

Yes. PF5, SbCl5 and other AB5 (sp3d) molecules show the same pattern: axial bonds are longer than equatorial bonds for the same reason - greater 90-degree repulsion on the axial positions.

Why does a lone pair go to the equatorial position but a longer bond stays axial?

A lone pair is more repulsive than a bond pair, so it prefers the roomier equatorial position (only two 90-degree neighbours). For bonds, the axial position is the more crowded one, which is why axial bonds are stretched longer. Both facts come from the same idea: 90-degree repulsion is strongest, and the equatorial site has less of it.

Is this concept important for NEET?

Yes. It is directly asked as a statement-based question (NEET 2022 and 2026) and supports many VSEPR and shape-matching questions. Knowing that axial bonds are longer and that PCl5 is therefore reactive can win you an easy mark.