Expanded Octet and Hypervalent Molecules (PF5, SF6)

Chemistry · Chemical Bonding · NEET

An expanded octet means the central atom holds MORE than 8 electrons in its outer shell. PF5 has 10 electrons and SF6 has 12 electrons around the central atom. This is only possible for elements in period 3 and below (like P, S, Cl, Xe) because they have empty 3d orbitals to use. Memory hook: "Big shell, more room" — bigger atoms with d orbitals can pack in extra electron pairs.
Expanded Octet: more than 8 electrons around central atomNormal octetCCCl4 = 8 e-PF5 (sp3d)P10 e- (5 bonds)SF6 (sp3d2)S12 e- (6 bonds)
Carbon (period 2) is capped at a normal octet of 8 electrons. Phosphorus and sulphur (period 3) use empty 3d orbitals to expand: PF5 packs 10 electrons and SF6 packs 12 electrons around the central atom.

Your doubts, answered

What exactly is an expanded octet?

An expanded octet is when the central atom of a molecule has MORE than 8 electrons in its valence (outer) shell. Normally atoms want exactly 8 electrons (the octet rule). But some atoms break this rule and hold 10, 12, or even 14 electrons. Example: in PF5, phosphorus makes 5 bonds, so it has 5 x 2 = 10 electrons around it. In SF6, sulphur makes 6 bonds, so it has 12 electrons. This is called an expanded octet, and such molecules are called hypervalent.

Why can PF5 exist but NF5 does not?

This is the most asked doubt. Both N and P are in Group 15, so both have 5 valence electrons. But nitrogen is in period 2 — it only has 2s and 2p orbitals, which together hold a MAXIMUM of 8 electrons. Nitrogen has NO d orbitals, so it can never go beyond an octet. Phosphorus is in period 3 — it has 3s, 3p AND empty 3d orbitals. Phosphorus can use these 3d orbitals to make room for extra electrons, so it forms PF5 with 10 electrons. Rule to remember: no d orbitals means no expanded octet.

Why do only third period and lower elements show expanded octet?

NCERT says it clearly: elements in and beyond the third period have 3d orbitals available for bonding, in addition to 3s and 3p. The energy of the 3d orbitals is close enough to 3s and 3p to be used for bonding. Period 2 elements (C, N, O, F) do not have this — their outer shell (n=2) has only s and p orbitals, capped at 8 electrons. So expanded octet is only seen in P, S, Cl, Br, I, Xe and similar heavier atoms.

How many electrons are around the central atom in PF5 and SF6?

Count the bonds and multiply by 2 (each bond = 1 shared pair = 2 electrons). In PF5, phosphorus forms 5 single bonds to 5 fluorine atoms, so 5 x 2 = 10 electrons around P. In SF6, sulphur forms 6 single bonds to 6 fluorine atoms, so 6 x 2 = 12 electrons around S. Both are more than 8, so both have an expanded octet.

Is expanded octet the same as an exception to the octet rule?

Yes. NCERT lists three exceptions (limitations) of the octet rule: (1) incomplete octet, like BCl3 with only 6 electrons; (2) odd-electron molecules, like NO and NO2; and (3) expanded octet, like PF5, SF6, PCl5, SF4, XeF2. Expanded octet is the third type of exception, where the atom has MORE than 8 electrons instead of exactly 8.

What does the word hypervalent mean?

Hypervalent means the central atom has a valence (number of bonds) that is too high for a simple octet. In other words, a hypervalent molecule is one whose central atom carries an expanded octet — more than 8 electrons. PF5 (10 electrons), SF6 (12 electrons), and IF7 (14 electrons) are all hypervalent. The hybridisation matches: PF5 is sp3d, SF6 is sp3d2, IF7 is sp3d3 — the d orbitals are how the extra space is made.

Does sulphur always show an expanded octet?

No, this is a common trap. NCERT points out that sulphur also forms compounds that OBEY the octet rule. For example, in sulphur dichloride (SCl2), the sulphur atom has a normal octet of 8 electrons. Having d orbitals available does NOT force expansion — it just makes expansion POSSIBLE. So SF6 expands (12 electrons) but SCl2 does not. Look at the actual number of bonds each time.

⚠️ The NEET trap
Nitrogen and phosphorus are in the same group, so if PF5 exists then NF5 must also exist.
NF5 does NOT exist. Phosphorus (period 3) has empty 3d orbitals to expand its octet to 10 electrons in PF5. Nitrogen (period 2) has only 2s and 2p orbitals, capped at 8 electrons, and no d orbitals — so it can never form NF5. Same group does not mean same maximum covalency.
🧠 Same group, different period. Only the atom WITH d orbitals can expand. No d, no expansion.

Real NEET questions

NEET 2023

Amongst the following, the total number of species NOT having eight electrons around the central atom in its outermost shell is: NH3, AlCl3, BeCl2, CCl4, PCl5

A · 3
B · 2
C · 4
D · 1
Solution: Check each central atom. NH3: nitrogen has 8 electrons (octet complete). CCl4: carbon has 8 electrons (octet complete). AlCl3: aluminium has only 6 electrons (incomplete octet). BeCl2: beryllium has only 4 electrons (incomplete octet). PCl5: phosphorus has 10 electrons (expanded octet). So AlCl3, BeCl2 and PCl5 do NOT have exactly eight electrons — that is 3 species. PCl5 is the expanded-octet example here: phosphorus in period 3 uses its 3d orbitals to hold 10 electrons. Answer: 3.
NEET 2026

The correct statement is:

A · Boron has a maximum covalency of four
B · Beryllium has three valence orbitals
C · Magnesium has a maximum covalency of four
D · Aluminium has five valence orbitals
Solution: Boron is a period-2 element with four valence orbitals (2s, 2px, 2py, 2pz) and NO d orbitals, so its maximum covalency is four (as in BF4- and BH4-). It can never expand beyond an octet. This is exactly why period-2 elements cannot form an expanded octet, unlike period-3 elements (Mg, Al, Si, P, S) which have vacant 3d orbitals available. Beryllium also has four valence orbitals (not three), so option B is wrong. Answer: A.

Solved Chemical Bonding NEET PYQs

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Frequently asked

Which molecules are the classic examples of expanded octet?

PF5 (10 electrons, sp3d), SF6 (12 electrons, sp3d2), PCl5 (10 electrons, sp3d), SF4 (10 electrons), XeF2 and XeF4, and IF7 (14 electrons, sp3d3). All have a central atom from period 3 or below with more than 8 valence electrons.

Why can sulphur have 12 electrons in SF6?

Sulphur is in period 3, so it has empty 3d orbitals whose energy is close to 3s and 3p. It uses sp3d2 hybridisation (mixing one 3s, three 3p and two 3d orbitals) to form six equal S-F bonds, giving an octahedral shape with 12 electrons around sulphur.

Do expanded-octet molecules break the octet rule?

Yes. The octet rule is a useful guide, mainly for period-2 elements, but it is not universal. Expanded octet is one of the three official NCERT exceptions to the octet rule, along with incomplete octet and odd-electron molecules.

What hybridisation goes with expanded octet?

Any hybridisation that uses d orbitals: sp3d (5 electron pairs, like PF5, PCl5), sp3d2 (6 pairs, like SF6), or sp3d3 (7 pairs, like IF7). Using d orbitals is what allows more than four bonds, and hence more than 8 electrons.

Is expanded octet important for NEET?

Yes, very. NEET regularly asks to identify exceptions to the octet rule (like the 2023 count question with PCl5) and to link period, d orbitals and maximum covalency (like the 2026 Boron question). Knowing PF5 = 10 and SF6 = 12 electrons, and that only period-3+ atoms can expand, wins these marks quickly.