Law of Conservation of Energy in Thermodynamics (First Law)

Chemistry · Thermodynamics · NEET

The law of conservation of energy says energy cannot be made from nothing and cannot vanish. It can only change form or move from one place to another. In chemistry this becomes the first law of thermodynamics: the change in internal energy equals heat plus work, written as ΔU = q + w. Memory hook: "Energy is like money in a sealed piggy bank — you can move it around, but the total never changes."
First Law: ΔU = q + w (Energy is Conserved)SYSTEMinternal energy UΔU = changeheat in +qwork done BY −wsurroundingsEnergy is not created or destroyed — only moved and changed.
Energy flows in as heat (+q) and out as work done by the system (−w); the internal energy change ΔU = q + w records the balance. The total energy is always conserved.

Your doubts, answered

Is the law of conservation of energy the same as the first law of thermodynamics?

Yes, they are the same idea. The law of conservation of energy is the general statement: energy cannot be created or destroyed. The first law of thermodynamics is this same law written for a thermodynamic system as ΔU = q + w. So the first law is just the conservation law applied to heat (q), work (w) and internal energy (U). NEET asks it both ways, so treat them as one concept.

If heat leaves the system, is that energy destroyed?

No. The energy is not destroyed, it only moves out to the surroundings. If the system loses heat, the surroundings gain exactly that much. The total energy of the universe (system + surroundings) stays the same. This is why an isolated system, which cannot exchange heat or matter, has constant internal energy (ΔU = 0).

Which formula is right for NEET, ΔU = q + w or ΔU = q − w?

NCERT and NEET use the modern IUPAC convention: ΔU = q + w. Here work done ON the system is positive (+w) and work done BY the system is negative (−w). The old physics form ΔU = q − W uses W as work done BY the system. Both give the same final answer; just do not mix them. For NEET always start from ΔU = q + w and put the correct sign on w.

How do I fix the signs of q and w?

Two simple rules. Heat: absorbed BY the system is +q, released by the system is −q. Work: done ON the system (compression) is +w, done BY the system (expansion) is −w. Example: if a gas absorbs 500 J and does 200 J of work, then q = +500, w = −200, so ΔU = 500 − 200 = +300 J.

Why can we only measure ΔU and not the absolute internal energy U?

Internal energy is the total of all molecular energies (kinetic, potential, bond, electronic). We cannot count all of these, so we never know the true value of U. But we can measure the CHANGE, ΔU, from heat and work using the first law. This is why every conservation-of-energy problem asks for ΔU, not U itself.

What does ΔU = 0 mean for an isolated system?

An isolated system exchanges neither heat nor matter with the surroundings, so q = 0 and no work crosses the boundary. Then ΔU = 0, meaning its internal energy is constant. NCERT states this directly: the energy of an isolated system is constant. This is the purest form of the conservation law.

⚠️ The NEET trap
For a gas that absorbs 500 J and does 200 J of work, students add both: ΔU = 500 + 200 = 700 J.
Work done BY the system is negative, so w = −200 J. ΔU = q + w = 500 + (−200) = +300 J.
🧠 'Done BY the system' always means minus. The system spends energy to push out, so subtract it.

Real NEET questions

2026

At a certain temperature T (K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then the change in internal energy of the system is:

A · 400 J
B · 300 J
C · 700 J
D · 500 J
Solution: Use the first law (conservation of energy): ΔU = q + w. Heat absorbed by the system is positive, so q = +500 J. Work done BY the system is negative, so w = −200 J. Therefore ΔU = 500 + (−200) = +300 J. Answer: B.
2017

A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ΔU of the gas in joules will be:

A · 1136.25 J
B · −500 J
C · −505 J
D · +505 J
Solution: Well insulated means adiabatic, so no heat crosses the boundary: q = 0. By conservation of energy ΔU = q + w = w. Work done on the gas against constant external pressure is w = −p(ext)ΔV = −2.5 × (4.50 − 2.50) = −5 L·atm. Convert: −5 × 101.3 J ≈ −505 J. Answer: C.

Solved Thermodynamics NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

See all 28 Thermodynamics NEET PYQs ›
Next concept: Work Done in Single-Step vs Multi-Step (Stepwise) CompressionKeep learning — 2 minFeeling ready? Solve the Thermodynamics NEET PYQs ›Or practice on your phone — get the free MedicNEET app ›

Frequently asked

State the law of conservation of energy in one line.

Energy can neither be created nor destroyed; it can only be transformed from one form to another or transferred from one body to another, so the total energy stays constant.

What is the mathematical form of the first law of thermodynamics?

ΔU = q + w, where ΔU is the change in internal energy, q is heat added to the system, and w is work done on the system.

Is the law of conservation of energy always true?

For NEET-level chemistry, yes. It holds for all ordinary chemical and physical processes. It is one of the most tested and reliable laws in the syllabus.

What happens to internal energy in an isolated system?

It stays constant. An isolated system cannot exchange heat or matter, so ΔU = 0. NCERT states the energy of an isolated system is constant.

Why does NEET prefer ΔU = q + w over ΔU = q − W?

NCERT follows the modern IUPAC sign convention where +w means work done ON the system. Using ΔU = q + w with correct signs avoids confusion, so stick to it for every NEET problem.