NEET 2016 Phase 1 · ChemistryPrevious Year Question
The reaction shown in the scheme can be classified as:
Answer: (A) Williamson ether synthesis reaction. \textbf{Answer:} (a) Williamson ether synthesis \textbf{Solution:} Cyclohexanol is first deprotonated by to give sodium cyclohexoxide (an alkoxide).
- A.Williamson ether synthesis reaction✓
- B.Alcohol formation reaction
- C.Dehydration reaction
- D.Williamson alcohol synthesis reaction
Correct Answer
(A) Williamson ether synthesis reaction
Solution & Explanation
\textbf{Answer:} (a) Williamson ether synthesis \textbf{Solution:} Cyclohexanol is first deprotonated by to give sodium cyclohexoxide (an alkoxide). This alkoxide then performs an attack on methyl iodide, displacing iodide and forming methyl cyclohexyl ether (). Formation of an ether from an alkoxide and an alkyl halide is the classic Williamson ether synthesis. Hence (a).
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