NEET 2016 Phase 2 · ChemistryPrevious Year Question

Hot concentrated sulphuric acid is a moderately strong oxidizing agent. Which of the following reactions does not show oxidizing behaviour?

Answer: (D) (d) $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ . \textbf{Answer:} (d) $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ \textbf{Solution:} In $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ there is no change in the oxidation state of any atom (Ca is +2, F is $- 1$ , S is +6, O is $- 2$ on both sides).

A.(a) $Cu + 2 H X_{2} SO X_{4} CuSO X_{4} + SO X_{2} + 2 H X_{2} O$
B.(b) $3 S + 2 H X_{2} SO X_{4} 3 SO X_{2} + 2 H X_{2} O$
C.(c) $C + 2 H X_{2} SO X_{4} CO X_{2} + 2 SO X_{2} + 2 H X_{2} O$
D.(d) $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ ✓

Correct Answer

(D) (d) $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$

Solution & Explanation

\textbf{Answer:} (d) $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ \textbf{Solution:} In $CaF X_{2} + H X_{2} SO X_{4} CaSO X_{4} + 2 HF$ there is no change in the oxidation state of any atom (Ca is +2, F is $- 1$ , S is +6, O is $- 2$ on both sides). It is a simple double-displacement / acid-salt reaction, not a redox process, so $H X_{2} SO X_{4}$ does not act as an oxidizing agent here. In (a), (b) and (c) sulphur in $H X_{2} SO X_{4}$ is reduced from +6 to +4 (as $SO X_{2}$ ) while $Cu$ , $S$ and $C$ are oxidized, so $H X_{2} SO X_{4}$ behaves as an oxidizing agent in those cases.

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