Suppose the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weighs 10 g and 0.05 mole of X3Y2 weighs 9 g, the atomic weights of X and Y respectively are

Correct answer: (A) 40, 30. Answer: (A) 40, 30 Solution: Molar mass of XY2 = 100.1 = 100 g mol-1, so X + 2Y = 100 ...(i) Molar mass of X3Y2 = 90.05 = 180 g mol-1, so 3X + 2Y = 180 ...(ii) Subtracting (i) from (ii): 2X = 80 X = 40. Then 2Y = 100 - 40 = 60 Y = 30.

NEET 2016 Phase 2 · ChemistryPrevious Year Question

Suppose the elements X and Y combine to form two compounds $XY X_{2}$ and $X X_{3} Y X_{2}$ . When 0.1 mole of $XY X_{2}$ weighs 10 g and 0.05 mole of $X X_{3} Y X_{2}$ weighs 9 g, the atomic weights of X and Y respectively are

Answer: (A) 40, 30. \textbf{Answer:} (A) 40, 30 \textbf{Solution:} Molar mass of $XY X_{2}$ $= \frac{10}{0.1} = 100$ g mol $^{- 1}$ , so $X + 2 Y = 100$ ...(i) Molar mass of $X X_{3} Y X_{2}$ $= \frac{9}{0.05} = 180$ g mol $^{- 1}$ , so $3 X + 2 Y = 180$ ...(ii) Subtracting (i) from (ii): $2 X = 80 \Rightarrow X = 40$ .

A.40, 30✓
B.60, 40
C.20, 30
D.30, 20

Correct Answer

(A) 40, 30

Solution & Explanation

\textbf{Answer:} (A) 40, 30 \textbf{Solution:} Molar mass of $XY X_{2}$ $= \frac{10}{0.1} = 100$ g mol $^{- 1}$ , so $X + 2 Y = 100$ ...(i) Molar mass of $X X_{3} Y X_{2}$ $= \frac{9}{0.05} = 180$ g mol $^{- 1}$ , so $3 X + 2 Y = 180$ ...(ii) Subtracting (i) from (ii): $2 X = 80 \Rightarrow X = 40$ . Then $2 Y = 100 - 40 = 60 \Rightarrow Y = 30$ .

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Suppose the elements X and Y combine to form two compounds XYX2​ and XX3​YX2​. When 0.1 mole of XYX2​ weighs 10 g and 0.05 mole of XX3​YX2​ weighs 9 g, the atomic weights of X and Y respectively are

Solution & Explanation

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Suppose the elements X and Y combine to form two compounds $XY X_{2}$ and $X X_{3} Y X_{2}$ . When 0.1 mole of $XY X_{2}$ weighs 10 g and 0.05 mole of $X X_{3} Y X_{2}$ weighs 9 g, the atomic weights of X and Y respectively are