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NEET 2017 · ChemistryPrevious Year Question

The IUPAC name of the compound shown (a six-carbon chain bearing a terminal , an adjacent branch, a ketone , and a double bond) is:

Answer: (A) 3-keto-2-methylhex-4-enal. \textbf{Answer:} (a) 3-keto-2-methylhex-4-enal \textbf{Solution:} The aldehyde () is the principal characteristic group and gets the lowest locant (C-1) with the suffix -al.

NEET 2017 Chemistry question — The IUPAC name of the compound shown (a six-carbon chain bearing a terminal -CHO, an…
  1. A.3-keto-2-methylhex-4-enal✓
  2. B.5-formylhex-2-en-3-one
  3. C.5-methyl-4-oxohex-2-en-5-al
  4. D.3-keto-2-methylhex-5-enal

Correct Answer

(A) 3-keto-2-methylhex-4-enal

Solution & Explanation

\textbf{Answer:} (a) 3-keto-2-methylhex-4-enal \textbf{Solution:} The aldehyde () is the principal characteristic group and gets the lowest locant (C-1) with the suffix -al. Numbering the six-carbon parent chain from the end: C-1 aldehyde, C-2 bears the methyl substituent, C-3 is the ketone (oxo/keto), and the double bond lies between C-4 and C-5. This gives 3-keto-2-methylhex-4-enal (aldehyde > ketone > alkene in priority for numbering). Hence (a).

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