The compound A on treatment with Na gives B, and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C, in order, are:

Correct answer: (D) (D) C2H5OH, C2H5ONa, C2H5Cl. A is ethanol C2H5OH. With sodium it gives sodium ethoxide, 2C2H5OH + 2Na -> 2C2H5ONa + H2 (B). With PCl5 it gives ethyl chloride, C2H5OH + PCl5 -> C2H5Cl + POCl3 + HCl (C). The Williamson synthesis C2H5ONa + C2H5Cl -> C2H5OC2H5 + NaCl then gives diethyl ether. Hence A, B, C = C2H5OH, C2H5ONa, C2H5Cl.

NEET 2018 · ChemistryPrevious Year Question

The compound A on treatment with $Na$ gives B, and with $PCl X_{5}$ gives C. B and C react together to give diethyl ether. A, B and C, in order, are:

Answer: (D) (D) $C X_{2} H X_{5} OH, C X_{2} H X_{5} ONa, C X_{2} H X_{5} Cl$ . A is ethanol $C X_{2} H X_{5} OH$ .

A.(A) $C X_{2} H X_{5} Cl, C X_{2} H X_{6}, C X_{2} H X_{5} OH$
B.(B) $C X_{2} H X_{5} OH, C X_{2} H X_{5} Cl, C X_{2} H X_{5} ONa$
C.(C) $C X_{2} H X_{5} OH, C X_{2} H X_{6}, C X_{2} H X_{5} Cl$
D.(D) $C X_{2} H X_{5} OH, C X_{2} H X_{5} ONa, C X_{2} H X_{5} Cl$ ✓

Correct Answer

(D) (D) $C X_{2} H X_{5} OH, C X_{2} H X_{5} ONa, C X_{2} H X_{5} Cl$

Solution & Explanation

A is ethanol $C X_{2} H X_{5} OH$ . With sodium it gives sodium ethoxide, $2 C X_{2} H X_{5} OH + 2 Na 2 C X_{2} H X_{5} ONa + H X_{2}$ (B). With $PCl X_{5}$ it gives ethyl chloride, $C X_{2} H X_{5} OH + PCl X_{5} C X_{2} H X_{5} Cl + POCl X_{3} + HCl$ (C). The Williamson synthesis $C X_{2} H X_{5} ONa + C X_{2} H X_{5} Cl C X_{2} H X_{5} OC X_{2} H X_{5} + NaCl$ then gives diethyl ether. Hence A, B, C $= C X_{2} H X_{5} OH, C X_{2} H X_{5} ONa, C X_{2} H X_{5} Cl$ .

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The compound A on treatment with Na gives B, and with PClX5​ gives C. B and C react together to give diethyl ether. A, B and C, in order, are:

Solution & Explanation

More NEET PYQ solutions

The compound A on treatment with $Na$ gives B, and with $PCl X_{5}$ gives C. B and C react together to give diethyl ether. A, B and C, in order, are: