NEET 2019 Odisha · ChemistryPrevious Year Question

The density of a 2 M aqueous solution of $NaOH$ is $1.28 g/cm^{3}$ . The molality of the solution is [Given that molar mass of $NaOH$ $= 40 g mol^{- 1}$ ]:

Answer: (C) 1.67 m. \textbf{Answer:} (C) 1.67 m \textbf{Solution:} Consider 1 L (1000 mL) of the 2 M solution → it contains 2 moles of $NaOH$ .

A.1.20 m
B.1.56 m
C.1.67 m✓
D.1.32 m

Correct Answer

Solution & Explanation

\textbf{Answer:} (C) 1.67 m \textbf{Solution:} Consider 1 L (1000 mL) of the 2 M solution → it contains 2 moles of $NaOH$ . Mass of solution $= 1000 \times 1.28 = 1280$ g. Mass of solute $= 2 \times 40 = 80$ g. Mass of solvent $= 1280 - 80 = 1200$ g $= 1.2$ kg. Molality $= \frac{2}{1.2} = 1.67 m$ .

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The density of a 2 M aqueous solution of NaOH is 1.28 g/cm3. The molality of the solution is [Given that molar mass of NaOH =40 g mol−1]:

Solution & Explanation

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The density of a 2 M aqueous solution of $NaOH$ is $1.28 g/cm^{3}$ . The molality of the solution is [Given that molar mass of $NaOH$ $= 40 g mol^{- 1}$ ]: