NEET 2019 Odisha · ChemistryPrevious Year Question

In water-saturated air the mole fraction of water vapour is 0.02. If the total pressure of the saturated air is 1.2 atm, the partial pressure of dry air is:

Answer: (C) 1.176 atm. \textbf{Answer:} (C) 1.176 atm \textbf{Solution:} Mole fraction of water vapour $x_{w a t er} = 0.02$ , so mole fraction of dry air $x_{d r y} = 1 - 0.02 = 0.98$ .

A.1.18 atm
B.1.76 atm
C.1.176 atm✓
D.0.98 atm

Correct Answer

Solution & Explanation

\textbf{Answer:} (C) 1.176 atm \textbf{Solution:} Mole fraction of water vapour $x_{w a t er} = 0.02$ , so mole fraction of dry air $x_{d r y} = 1 - 0.02 = 0.98$ . By Dalton's law, partial pressure $=$ mole fraction $\times$ total pressure: $p_{d r y ai r} = 0.98 \times 1.2 = 1.176$ atm.

🎯

43,000+ questions in हिंदी & English · one-tap toggle

Practice NEET 2019 Odisha Chemistry — free, with instant solutions

43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.

Open →📚Practice all NEET Chemistry PYQs chapter-wise →💡Don't get it? Learn the Solutions concepts →

← Chemistry Q8 Chemistry Q10 →

More NEET PYQ solutions

ChemIdentify the suitable reagent for the following conversion: C6H5COOCH3 -> C6H5CHO (methyl benzoate to benzaldehyde)ChemThe correct order of decreasing acidity of the following aliphatic acids is ChemThe major product of the following reaction is: 4-oxo-4-phenylbutanenitrile C6H5-CO-CH2-CH2-CN is treated with (i) CH3MgBr (excess) and then (ii) H3O+.ChemOut of the following complex compounds, which compound will have the minimum conductance in solution?ChemWhich of the following are paramagnetic? A. [NiCl4]^2- B. Ni(CO)4 C. [Ni(CN)4]^2- D. [Ni(H2O)6]^2+ E. Ni(PPh3)4 ChemThe correct order of the wavelength of light absorbed by the following complexes is: A. [Co(NH3)6]^3+ B. [Co(CN)6]^3- C. [Cu(H2O)4]^2+ D. [Ti(H2O)6]^3+ChemThe correct order of decreasing basic strength of the given amines is: (N-ethylethanamine = (C2H5)2NH; ethanamine = C2H5NH2; N-methylaniline = C6H5NH(CH3); benzenamine/aniline = C6H5NH2)ChemPredict the major product P in the following sequence of reactions. The starting material is 1-methylcyclopent-1-ene: (i) HBr, benzoyl peroxide; (ii) KCN; (iii) Na(Hg)/C2H5OH P (major). The structures of the options (A)-(D) are shown in the image below:

More: All NEET 2019 Odisha Chemistry PYQs · NEET Chemistry PYQs · All NEET PYQs · Previous year papers