NEET 2024 · ChemistryPrevious Year Question

A compound X contains 32\% of A, 20\% of B and the remaining percentage of C. The empirical formula of X is (atomic masses: A = 64, B = 40, C = 32 u)

Answer: (A) $ABC X_{3}$ . \textbf{Answer:} (A) $ABC X_{3}$ \textbf{Solution:} C\% $= 100 - 32 - 20 = 48%$ .

A. $ABC X_{3}$ ✓
B. $AB X_{2} C X_{2}$
C. $ABC X_{4}$
D. $A X_{2} BC X_{2}$

Correct Answer

(A) $ABC X_{3}$

Solution & Explanation

\textbf{Answer:} (A) $ABC X_{3}$ \textbf{Solution:} C\% $= 100 - 32 - 20 = 48%$ . Moles: A $= \frac{32}{64} = 0.5$ ; B $= \frac{20}{40} = 0.5$ ; C $= \frac{48}{32} = 1.5$ . Divide by smallest (0.5): A : B : C $= 1 : 1 : 3$ . Empirical formula $=$ $ABC X_{3}$ .

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