Dot Product (Scalar Product) of Two Vectors and Work Done

Physics · Motion In A Plane · NEET

The dot product (scalar product) of two vectors A and B is A.B = AB cos theta, where theta is the angle between them; the answer is a scalar (a plain number, no direction). In component form A.B = Ax*Bx + Ay*By + Az*Bz. This is exactly how work done is found: W = F.d = Fd cos theta. Memory hook: "Dot gives a number, cos rides with the dot."
Dot Product: A . B = A B cosθ (a scalar)ABθprojection of B on A = B cosθA . B = (B cosθ) × AWork: W = F . d = F d cosθIf θ = 90°: cos90 = 0 → A . B = 0(vectors perpendicular, no work)Components: A . B = AxBx + AyBy + AzBz
The dot product A.B equals the magnitude of A times the projection of B along A (B cos theta), giving a scalar. When theta = 90 degrees the projection is zero, so the dot product and the work done both become zero.

Your doubts, answered

Is the dot product a scalar or a vector?

It is always a scalar, meaning just a number with a unit but no direction. Even though you multiply two vectors, the cos theta term projects one vector onto the other, so the result loses direction. That is why it is called the scalar product. Remember: dot -> scalar, cross -> vector.

Why is work done written as a dot product W = F.d?

Work is done only by the part of the force that acts along the direction of motion. The dot product F.d = Fd cos theta automatically picks out that along-the-motion part (F cos theta) and multiplies it by the distance d. If the force is perpendicular to the motion (theta = 90 degrees), cos 90 = 0, so no work is done, which matches real physics like circular motion.

What does it mean if the dot product of two vectors is zero?

If A.B = 0 and neither vector is zero, then cos theta = 0, so theta = 90 degrees. The two vectors are perpendicular. This is a fast NEET test: to check if two vectors are at right angles, just compute Ax*Bx + Ay*By + Az*Bz and see if it equals zero.

Does the dot product use cos or sin?

The dot product uses cos: A.B = AB cos theta. The cross product uses sin. A simple way to keep them apart: the do-T product and cos-Theta both feel 'flat/along', while sin (cross) gives the perpendicular area. Mixing them up is the most common NEET error here.

How do I find the dot product from i, j, k components?

Multiply matching components and add: if A = Ax i + Ay j + Az k and B = Bx i + By j + Bz k, then A.B = Ax*Bx + Ay*By + Az*Bz. This works because i.i = j.j = k.k = 1 and i.j = j.k = k.i = 0. No angle needed.

What is A.A, the dot product of a vector with itself?

A.A = A*A*cos 0 = A^2, the square of its magnitude. So the magnitude of a vector is A = sqrt(A.A) = sqrt(Ax^2 + Ay^2 + Az^2). This link between dot product and magnitude is used a lot in energy problems.

⚠️ The NEET trap
Using A.B = AB sin theta or expecting the dot product to give a vector answer with a direction.
The dot product is A.B = AB cos theta and the answer is a scalar (a plain number). sin theta belongs to the cross product.
🧠 Dot = cos = number. Cross = sin = vector. If your dot product answer has i, j, k in it, you made a mistake.

Real NEET questions

2016

A particle moves from a point (-2 i + 5 j) to (4 j + 3 k) when a force of (4 i + 3 j) N is applied. How much work is done by the force?

A · 8 J
B · 11 J
C · 5 J
D · 2 J
Solution: Step 1: Find the displacement d = final - initial = (0 i + 4 j + 3 k) - (-2 i + 5 j + 0 k) = 2 i - 1 j + 3 k (in metres). Step 2: Work is a dot product, W = F.d. With F = 4 i + 3 j + 0 k, multiply matching components and add: W = (4)(2) + (3)(-1) + (0)(3) = 8 - 3 + 0 = 5. Step 3: So W = 5 J, option C.
2016

If the magnitude of the sum of two vectors is equal to the magnitude of the difference of the two vectors, the angle between these vectors is:

A · 0 degrees
B · 90 degrees
C · 45 degrees
D · 180 degrees
Solution: Step 1: |A + B|^2 = A^2 + B^2 + 2 A.B and |A - B|^2 = A^2 + B^2 - 2 A.B. Step 2: Setting them equal gives 2 A.B = -2 A.B, so 4 A.B = 0, meaning A.B = 0. Step 3: Since A.B = AB cos theta = 0, cos theta = 0, so theta = 90 degrees. The vectors are perpendicular, option B. This directly uses the zero-dot-product rule.

Solved Motion In A Plane NEET PYQs

Try the real previous-year questions from this chapter — each with the answer and a full solution.

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Frequently asked

Is the dot product commutative?

Yes. A.B = B.A because AB cos theta does not depend on the order. This is different from the cross product, which changes sign when you swap the order.

What is the SI unit of the dot product in work?

When force (newton) is dotted with displacement (metre), the result W = F.d has the unit newton-metre, which is the joule (J), the unit of energy.

Can the dot product be negative?

Yes. If theta is between 90 and 180 degrees, cos theta is negative, so A.B is negative. In work, a negative dot product means the force opposes the motion, like friction doing negative work.

What is the dot product of two unit vectors i and j?

i.j = 0 because they are perpendicular (cos 90 = 0). But i.i = 1 because a unit vector dotted with itself gives cos 0 = 1.

How is the dot product used to find the angle between two vectors?

Rearrange the formula: cos theta = (A.B) / (AB). Compute A.B from components, divide by the product of the magnitudes, then take the inverse cosine to get theta.