Difference Between Heat, Work and Internal Energy

Physics · Thermodynamics · NEET

Heat (Q) and work (W) are two ways energy MOVES between a system and its surroundings, while internal energy (U) is the total energy STORED inside the gas. Heat flows because of a temperature difference; work is done when the gas pushes or is pushed (volume changes). Memory hook: Heat and Work are like MONEY MOVING in and out; Internal Energy is the BALANCE already sitting in the bank account.
Internal Energy U(stored inside)state functionHeat Q in(temp difference)Work W out(volume change)Q = delta U + WHeat and Work are energy in transit; U is stored
Heat Q flows IN due to a temperature difference and work W leaves as the gas expands; both are energy in transit across the boundary. Only internal energy U is stored inside, and the three are linked by the first law Q = delta U + W.

Your doubts, answered

Is heat the same as internal energy? They both sound like 'thermal energy'.

No. Internal energy (U) is energy already stored inside the gas: the kinetic energy of its moving molecules (and potential energy of interactions). Heat (Q) is energy that FLOWS in or out only because two bodies are at different temperatures. You cannot say a gas 'contains 50 J of heat'; you can only say 50 J of heat FLOWED into it. Once inside, that energy becomes part of the internal energy. So heat is a transfer process, internal energy is a stored amount.

Why are heat and work called 'energy in transit' but not internal energy?

Heat and work only exist while energy is crossing the boundary of the system. A gas sitting alone has an internal energy, but it has no heat and no work at that moment. Heat and work are like the act of transferring money; internal energy is the balance in the account. That is why we write a small change as delta U (a change in a stored quantity), but we just write Q and W (amounts transferred), not delta Q or delta W.

Are heat and work state functions or path functions?

Internal energy (U) is a STATE function: it depends only on the current state (mainly temperature for an ideal gas), not on how the gas got there. Heat (Q) and work (W) are PATH functions: their values depend on the route taken on the P-V diagram. Two different paths between the same start and end points give the SAME delta U but usually DIFFERENT Q and W. This is exactly what NEET 2025 tested.

If I add heat to a gas, does its internal energy always increase?

Not always. By the first law, delta U = Q - W. If the gas absorbs heat Q but also does work W by expanding, the internal energy rises only by the leftover (Q - W). In an isothermal expansion the gas absorbs heat but ALL of it becomes work, so delta U = 0 and temperature does not change. In an adiabatic expansion Q = 0, yet the gas still does work, so internal energy (and temperature) FALLS.

Does a gas 'have' work stored in it?

No. A gas never 'contains' work, just as it never 'contains' heat. Work is energy transferred when the gas volume changes against a pressure. Once the piston stops moving, there is no work anymore; the transferred energy has become part of the internal energy (or was supplied by it). Only internal energy is stored in the gas.

⚠️ The NEET trap
A gas at high temperature contains a large amount of heat.
A hot gas has a large INTERNAL ENERGY. Heat is only the energy that FLOWS due to a temperature difference; a gas does not 'contain' heat.
🧠 NTA loves the phrase 'amount of heat in the gas'. Heat and work are energy in transit, never a property stored in the system. Only internal energy is stored. If an option says a body 'possesses heat', it is testing this trap.

Real NEET questions

NEET 2026

At a certain temperature, during a process, 500 J is absorbed by the system and 200 J of work is done by the system. The change in internal energy of the system is

A · 400 J
B · 300 J
C · 700 J
D · 500 J
Solution: Use the first law of thermodynamics: delta U = Q - W. Step 1: Heat absorbed BY the system is positive, so Q = +500 J. Step 2: Work done BY the system is positive, so W = +200 J. Step 3: delta U = Q - W = 500 - 200 = 300 J. This separates the three ideas: 500 J of heat came IN, 200 J left AS work, and the remaining 300 J was STORED as internal energy. Answer: (B) 300 J.
NEET 2026

An electric heater supplies heat to a system at a rate of 100 W. If the system performs work at a rate of 75 J/s, the rate at which internal energy increases is

A · 75 W
B · 100 W
C · 125 W
D · 25 W
Solution: Write the first law in rate form: dQ/dt = dU/dt + dW/dt. Step 1: Rate of heat supplied dQ/dt = 100 W. Step 2: Rate of work done by the system dW/dt = 75 J/s = 75 W. Step 3: Rate of internal-energy increase dU/dt = dQ/dt - dW/dt = 100 - 75 = 25 W. Notice heat (in) and work (out) are transfers, and only the leftover 25 W per second is stored inside. Answer: (D) 25 W.
NEET 2025

Two gases A and B are filled at the same pressure in separate cylinders with movable pistons of radius r_A and r_B. On supplying an equal amount of heat to both gases reversibly at constant pressure, the pistons of A and B are displaced by 16 cm and 9 cm respectively. If the change in their internal energy is the same, then the ratio r_A / r_B is

A · 2/3
B · 3/2
C · 4/3
D · 3/4
Solution: Use the first law Q = delta U + W to SEPARATE the three quantities. Step 1: Both gases get equal heat Q, and equal change in internal energy delta U is given. So the work done must be equal: W_A = W_B. Step 2: At constant pressure, W = P (delta V) = P (pi r^2) d, where d is the piston displacement. Step 3: With equal P, set W_A = W_B: r_A^2 (d_A) = r_B^2 (d_B), so r_A^2 (16) = r_B^2 (9). Step 4: (r_A/r_B)^2 = 9/16, therefore r_A/r_B = 3/4. This works only because Q, W and delta U are three separate quantities linked by the first law. Answer: (D) 3/4.

Solved Thermodynamics NEET PYQs

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Frequently asked

What is the one-line difference between heat, work and internal energy?

Heat and work are energy in TRANSIT across the boundary (heat due to temperature difference, work due to volume change), while internal energy is the energy STORED inside the system.

What is the unit of heat, work and internal energy?

All three are forms of energy, so all are measured in joules (J). Heat is also sometimes given in calories, where 1 cal = 4.2 J.

Which of these is a state function?

Only internal energy is a state function; it depends solely on the state (mainly temperature for an ideal gas). Heat and work are path functions that depend on the process taken.

Can internal energy change without any heat being added?

Yes. In an adiabatic process Q = 0, but if the gas is compressed, work is done ON it and its internal energy (and temperature) rises. So delta U = -W.

Why do we write delta U but not delta Q or delta W?

Because U is a stored state quantity, so a change in it makes sense (delta U). Heat and work are amounts transferred, not stored, so we write just Q and W, meaning 'the heat transferred' and 'the work done'.