The hybridizations of the atomic orbitals of nitrogen in NO2+, NO3^- and NH4+ respectively are

Correct answer: (C) sp, sp^2 and sp^3. Answer: (C) sp, sp^2 and sp^3 Solution: NO2+ is linear (2 sigma, no lone pair) → sp; NO3^- is trigonal planar (3 sigma regions) → sp^2; NH4+ is tetrahedral (4 sigma) → sp^3.

NEET 2016 Phase 2 · ChemistryHybridisationPrevious Year Question

The hybridizations of the atomic orbitals of nitrogen in $NO X_{2} X^{+}$ , $NO X_{3} X^{-}$ and $NH X_{4} X^{+}$ respectively are

Answer: (C) $s p$ , $s p^{2}$ and $s p^{3}$ . \textbf{Answer:} (C) $s p$ , $s p^{2}$ and $s p^{3}$ \textbf{Solution:} $NO X_{2} X^{+}$ is linear (2 sigma, no lone pair) → $s p$ ; $NO X_{3} X^{-}$ is trigonal planar (3 sigma regions) → $s p^{2}$ ; $NH X_{4} X^{+}$ is tetrahedral (4 sigma) → $s p^{3}$ .

A. $s p$ , $s p^{3}$ and $s p^{2}$
B. $s p^{3}$ , $s p^{2}$ and $s p$
C. $s p$ , $s p^{2}$ and $s p^{3}$ ✓
D. $s p^{2}$ , $s p$ and $s p^{3}$

Correct Answer

Solution & Explanation

\textbf{Answer:} (C) $s p$ , $s p^{2}$ and $s p^{3}$ \textbf{Solution:} $NO X_{2} X^{+}$ is linear (2 sigma, no lone pair) → $s p$ ; $NO X_{3} X^{-}$ is trigonal planar (3 sigma regions) → $s p^{2}$ ; $NH X_{4} X^{+}$ is tetrahedral (4 sigma) → $s p^{3}$ .

🎯

43,000+ questions in हिंदी & English · one-tap toggle

Practice NEET 2016 Phase 2 Chemistry — free, with instant solutions

43,000+ NEET questions solved step-by-step, chapter-wise, in the MedicNEET app.

Open →📚Practice all NEET Chemistry PYQs chapter-wise →💡Don't get it? Learn the Chemical Bonding concepts →

← Chemistry Q1 Chemistry Q3 →

More NEET PYQ solutions

ChemMatch List-I with List-II. List-I (Molecule): A. ethane; B. ethene; C. carbon molecule, C2; D. ethyne List-II (Number and types of bond/s between the two carbon atoms): I. one -bond and two -bonds; II. two -bonds; III. one -bond; IV. one -bond and one -bond Choose the correct answer from the options given below:ChemThe number of bonds, bonds and lone pairs of electrons in pyridine (C5H5N), respectively, are:ChemBF3 is planar and an electron-deficient compound. The hybridization and number of electrons around the central atom, respectively, are:ChemThe number of sigma ( ) and pi ( ) bonds in pent-2-en-4-yne is ChemAluminium chloride in acidified aqueous solution forms a complex 'A', in which the hybridisation state of Al is 'B'. What are 'A' and 'B', respectively?ChemWhich of the following molecules represents the order of hybridisation sp^2, sp^2, sp, sp from left to right atoms?ChemThe lone pair of electrons in the given carbanion, CH3-C#C^-, is present in which of the following orbitals?ChemThe correct order of decreasing acidity of the following aliphatic acids is:

More: All NEET 2016 Phase 2 Chemistry PYQs · NEET Chemistry PYQs · All NEET PYQs · Previous year papers

The hybridizations of the atomic orbitals of nitrogen in NOX2​X+, NOX3​X− and NHX4​X+ respectively are

Solution & Explanation

More NEET PYQ solutions

The hybridizations of the atomic orbitals of nitrogen in $NO X_{2} X^{+}$ , $NO X_{3} X^{-}$ and $NH X_{4} X^{+}$ respectively are