NEET 2024 · ChemistryHybridisationPrevious Year Question
Match List-I with List-II. List-I (Molecule): A. ethane; B. ethene; C. carbon molecule, ; D. ethyne List-II (Number and types of bond/s between the two carbon atoms): I. one -bond and two -bonds; II. two -bonds; III. one -bond; IV. one -bond and one -bond Choose the correct answer from the options given below:
Answer: (B) A-III, B-IV, C-II, D-I. \textbf{Answer:} (B) A-III, B-IV, C-II, D-I \textbf{Solution:} Ethane () (III); ethene () (IV); by MOT has bond order made of two -bonds and no (II); ethyne () (I).
- A.A-IV, B-III, C-II, D-I
- B.A-III, B-IV, C-II, D-I✓
- C.A-III, B-IV, C-I, D-II
- D.A-I, B-IV, C-II, D-III
Correct Answer
(B) A-III, B-IV, C-II, D-I
Solution & Explanation
\textbf{Answer:} (B) A-III, B-IV, C-II, D-I \textbf{Solution:} Ethane () (III); ethene () (IV); by MOT has bond order made of two -bonds and no (II); ethyne () (I). So A-III, B-IV, C-II, D-I.
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