NEET 2019 · ChemistryHybridisationPrevious Year Question

Aluminium chloride in acidified aqueous solution forms a complex 'A', in which the hybridisation state of Al is 'B'. What are 'A' and 'B', respectively?

Answer: (A) $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $s p^{3} d^{2}$ . \textbf{Answer:} (A) $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $s p^{3} d^{2}$ \textbf{Solution:} In acidified aqueous solution $AlCl X_{3}$ forms the hexaaqua complex $[Al (H X_{2} O) X_{6}] X^{3 +}$ with coordination number 6; the six water ligands around $Al X^{3 +}$ require $s p^{3} d^{2}$ hybridisation (octahedral).

A. $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $s p^{3} d^{2}$ ✓
B. $[Al (H X_{2} O) X_{4}] X^{3 +}$ , $s p^{3}$
C. $[Al (H X_{2} O) X_{4}] X^{3 +}$ , $d s p^{2}$
D. $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $d^{2} s p^{3}$

Correct Answer

(A) $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $s p^{3} d^{2}$

Solution & Explanation

\textbf{Answer:} (A) $[Al (H X_{2} O) X_{6}] X^{3 +}$ , $s p^{3} d^{2}$ \textbf{Solution:} In acidified aqueous solution $AlCl X_{3}$ forms the hexaaqua complex $[Al (H X_{2} O) X_{6}] X^{3 +}$ with coordination number 6; the six water ligands around $Al X^{3 +}$ require $s p^{3} d^{2}$ hybridisation (octahedral).

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