The number of $\sigma$ bonds, $\pi$ bonds and lone pairs of electrons in pyridine ($\mathrm{C}{}_5\mathrm{H}{}_5\mathrm{N}$), respectively, are:

Solution & Explanation

\textbf{Answer:} (C) $11$, $3$, $1$ \textbf{Solution:} Pyridine has $5$ $\mathrm{C}-\mathrm{H}$ $\sigma$ bonds $+$ $6$ ring $\sigma$ bonds ($5$ $\mathrm{C}$ and $1$ $\mathrm{N}$ in the ring) $=11$ $\sigma$ bonds; the aromatic ring has $3$ $\pi$ bonds; the nitrogen carries $1$ lone pair. Hence $11$, $3$, $1$.