The number of sigma ( ) and pi ( ) bonds in pent-2-en-4-yne is

Correct answer: (A) 10 bonds and 3 bonds. Answer: (A) 10 bonds and 3 bonds Solution: Pent-2-en-4-yne is CH3-CH=CH-C#CH. Counting all bonds gives 10 bonds (every single bond plus the component of the double and triple bonds) and 3 bonds (1 from the C=C double bond + 2 from the C#C triple bond).

NEET 2019 · ChemistryHybridisationPrevious Year Question

The number of sigma ( $σ$ ) and pi ( $π$ ) bonds in pent-2-en-4-yne is

Answer: (A) $10$ $σ$ bonds and $3$ $π$ bonds. \textbf{Answer:} (A) $10$ $σ$ bonds and $3$ $π$ bonds \textbf{Solution:} Pent-2-en-4-yne is $CH X_{3} - CH = CH - C \equiv CH$ .

A. $10$ $σ$ bonds and $3$ $π$ bonds✓
B. $8$ $σ$ bonds and $5$ $π$ bonds
C. $11$ $σ$ bonds and $2$ $π$ bonds
D. $13$ $σ$ bonds and no $π$ bonds

Correct Answer

(A) $10$ $σ$ bonds and $3$ $π$ bonds

Solution & Explanation

\textbf{Answer:} (A) $10$ $σ$ bonds and $3$ $π$ bonds \textbf{Solution:} Pent-2-en-4-yne is $CH X_{3} - CH = CH - C \equiv CH$ . Counting all bonds gives $10$ $σ$ bonds (every single bond plus the $σ$ component of the double and triple bonds) and $3$ $π$ bonds ( $1$ from the $C = C$ double bond $+$ $2$ from the $C \equiv C$ triple bond).

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The number of sigma (σ) and pi (π) bonds in pent-2-en-4-yne is

Solution & Explanation

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The number of sigma ( $σ$ ) and pi ( $π$ ) bonds in pent-2-en-4-yne is