Binding Energy of a Satellite Explained

Physics · Gravitation · NEET

The binding energy of a satellite is the extra energy you must supply to just free it from Earth's gravity (send it to infinity with zero speed). It equals the magnitude of its total energy: Binding Energy = GMm/2r, where r is the orbit radius from Earth's centre. Memory hook: "Binding Energy = minus of Total Energy" — since a bound satellite has total energy E = -GMm/2r, you must add exactly +GMm/2r to set it free.
Energy of a Satellite in Orbit (radius r)Energy0 (at infinity)KE=+GMm/2rPE=-GMm/rE=-GMm/2rAdd Binding Energy= +GMm/2r-GMm/2r -> 0Satellite set freeTotal E is negative -> satellite is bound
A satellite has KE = +GMm/2r and PE = -GMm/r, giving total energy E = -GMm/2r (negative, so bound). Binding energy is the +GMm/2r you must add to raise its total energy to zero and free it to infinity.

Your doubts, answered

Is binding energy of a satellite positive or negative?

Binding energy is always POSITIVE. It is the energy you must ADD to the satellite to just free it. The total energy of the orbiting satellite is negative (E = -GMm/2r), and binding energy is the magnitude of that negative energy: BE = -E = +GMm/2r. A negative total energy is the sign that the satellite is bound; the positive binding energy is how much you pay to unbind it.

What is the difference between binding energy and total energy of a satellite?

They are equal in size but opposite in sign. Total energy E = -GMm/2r (negative, tells you the satellite is trapped). Binding energy = |E| = +GMm/2r (positive, the energy needed to escape to infinity with zero final speed). In one line: Binding Energy = -(Total Energy). If a question gives you total energy as -X, the binding energy is +X.

Is binding energy equal to the kinetic energy of a satellite?

Yes, numerically. For a circular orbit, KE = +GMm/2r and total energy E = -GMm/2r, so binding energy = |E| = GMm/2r = KE. So the binding energy of an orbiting satellite exactly equals its kinetic energy in orbit. But be careful: this equality holds only in circular orbit; it does not mean binding energy and KE are the same concept.

Why is binding energy GMm/2r and not GMm/r?

GMm/r is the potential energy magnitude at radius r (that would be the binding energy for a body sitting at rest at r). But a satellite is already MOVING with orbital kinetic energy KE = +GMm/2r. That orbital motion already supplies half the energy needed to escape. So you only need to add the remaining GMm/2r. Total energy = KE + PE = GMm/2r + (-GMm/r) = -GMm/2r, giving binding energy GMm/2r.

How do I write binding energy using g and R instead of GM?

Use GM = gR^2, where g is surface gravity and R is Earth's radius. Substitute into BE = GMm/2r to get BE = mgR^2/2r. For a satellite at height h, r = R + h, so BE = mgR^2 / [2(R+h)]. For a satellite skimming the surface (h = 0, r = R), this simplifies to BE = mgR/2.

⚠️ The NEET trap
Using the potential energy magnitude GMm/r as the binding energy, forgetting the satellite is already moving.
A satellite in orbit already has kinetic energy GMm/2r. Binding energy = -(total energy) = GMm/2r, NOT GMm/r. Only for a body AT REST at radius r would the binding energy be GMm/r.
🧠 Moving satellite -> divide by 2. Resting body -> no divide. If it orbits, binding energy is half of GMm/r.

Real NEET questions

2016

A satellite of mass m orbits the earth (radius R) at height h. In terms of g0 (surface gravity), the total energy of the satellite is:

A · mg0R^2 / 2(R+h)
B · -mg0R^2 / 2(R+h)
C · 2mg0R^2 / (R+h)
D · -2mg0R^2 / (R+h)
Solution: Step 1: Total energy of a satellite in circular orbit of radius r = R + h is E = -GMm / 2r = -GMm / 2(R+h). Step 2: Replace GM using GM = g0 R^2 (surface gravity relation). Step 3: E = -m g0 R^2 / 2(R+h). This is negative because the satellite is bound. Note: the binding energy is the positive magnitude of this, BE = +m g0 R^2 / 2(R+h).

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Frequently asked

What is the binding energy of a satellite in one line?

It is the minimum extra energy needed to remove the satellite from its orbit and take it to infinity with zero speed. BE = GMm/2r = |total energy|.

What is the binding energy of a satellite very close to Earth's surface?

Put r = R (Earth's radius): BE = GMm/2R = mgR/2, since GM = gR^2. This is the smallest orbit, so it needs the most binding energy per unit total energy compared to higher orbits.

Does binding energy increase or decrease with orbit height?

BE = GMm/2r decreases as r increases. A satellite in a higher orbit is more loosely bound, so less extra energy is needed to free it. As r tends to infinity, binding energy tends to zero.

Is binding energy the same as escape energy?

For an orbiting satellite, binding energy IS the energy to escape from that orbit: BE = GMm/2r. But 'escape energy from the surface' is different (GMm/R for a body at rest on the surface). Always check whether the body is orbiting or at rest.

Why does a negative total energy mean the satellite is bound?

Negative total energy means the satellite does not have enough energy to reach infinity (where PE = 0, KE >= 0, so E >= 0). Being short of that zero by GMm/2r is exactly the binding energy you must supply.