Minimum Energy to Launch a Satellite Into Orbit

Physics · Gravitation · NEET

The minimum energy to launch a satellite is the extra energy you must give it, so it moves from resting on Earth's surface into its final orbit. You find it as E_needed = E_orbit − E_surface, where E_orbit = −GMm / 2r (r is the orbit radius from Earth's centre) and E_surface = −GMm / R (R is Earth's radius). Memory hook: "final minus start" — subtract the negative surface energy from the negative orbit energy, and the answer always comes out positive.
Energy of the satellite: surface vs orbitE = 0 (at infinity)SurfaceE = -GMm/ROrbit (r=3R)E = -GMm/6RE needed = 5GMm/6R(orbit - surface)
Energy ladder for the NEET 2024 case: the satellite starts on the surface at −GMm/R and must be raised to the orbit level −GMm/6R (r = 3R). The green arrow (final − initial) is the minimum energy needed = 5GMm/6R.

Your doubts, answered

Is the minimum energy to launch the same as escape energy?

No. Escape energy sends the satellite to infinity with zero speed, so its final total energy is 0. Launch-into-orbit energy leaves the satellite in a bound orbit, so its final total energy is still negative (−GMm/2r). Launching into an orbit always needs less energy than fully escaping, because you do not have to climb all the way to zero energy.

Why do we subtract the surface energy instead of just using the orbit energy?

The satellite is not starting from rest at infinity — it starts sitting on Earth's surface, where it already has potential energy −GMm/R. Minimum energy is only the extra amount you must add. So E_needed = E_final − E_initial = E_orbit − E_surface. Subtracting a negative number makes the result larger and positive, which is correct.

Does the satellite on the ground have any kinetic energy?

In the standard NEET model we ignore Earth's rotation, so the satellite on the surface is treated as at rest with kinetic energy = 0. Its total energy on the surface is just its potential energy, E_surface = −GMm/R. This keeps the calculation clean and is what the 2024 NEET question expects.

What is the minimum energy when the orbit is at altitude 2R above the surface?

Altitude means height above the surface. If altitude = 2R, the orbit radius from Earth's centre is r = R + 2R = 3R. Then E_orbit = −GMm/(2 × 3R) = −GMm/6R and E_surface = −GMm/R, so E_needed = −GMm/6R − (−GMm/R) = 5GMm/6R. This is the exact NEET 2024 answer.

How is launch energy different from binding energy?

Binding energy is the energy needed to remove an already-orbiting satellite from its orbit to infinity: it equals +GMm/2r. Launch energy starts from the ground, not from orbit. So launch energy = binding-energy step plus the extra energy to first lift the satellite off the surface into the orbit.

⚠️ The NEET trap
Using r = 2R (treating altitude 2R as the orbit radius) and getting −GMm/4R for E_orbit, then a wrong final answer like 3GMm/4R.
Altitude is measured from the surface. Orbit radius from the centre is r = R + altitude = R + 2R = 3R, giving E_orbit = −GMm/6R and E_needed = 5GMm/6R.
🧠 Altitude is height above the ground; orbit radius is from Earth's centre. Always add R to the altitude before you use the energy formula.

Real NEET questions

2024

The minimum energy required to launch a satellite of mass m from the surface of the earth (mass M, radius R) into a circular orbit at an altitude 2R from the surface is:

A · 3GmM/2R
B · GmM/2R
C · GmM/3R
D · 5GmM/6R
Solution: Step 1 — Find the orbit radius. Altitude is measured from the surface, so orbit radius from Earth's centre is r = R + 2R = 3R. Step 2 — Total energy in orbit. For a circular orbit, E_orbit = −GMm/(2r) = −GMm/(2 × 3R) = −GMm/6R. Step 3 — Total energy on the surface. On the ground the satellite is at rest (KE = 0), so E_surface = −GMm/R. Step 4 — Minimum energy = final − initial. E_needed = E_orbit − E_surface = (−GMm/6R) − (−GMm/R) = −GMm/6R + GMm/R = (−1 + 6)GMm/6R = 5GMm/6R. Answer: D, 5GMm/6R.

Solved Gravitation NEET PYQs

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Frequently asked

What is the formula for minimum energy to launch a satellite into orbit?

E_needed = E_orbit − E_surface = (−GMm/2r) − (−GMm/R) = GMm/R − GMm/2r, where R is Earth's radius and r is the orbit radius from Earth's centre. Always add the altitude to R to get r.

For an orbit close to Earth's surface (r ≈ R), what is the minimum launch energy?

Put r = R: E_needed = GMm/R − GMm/2R = GMm/2R. So the minimum energy to just place a satellite in a low orbit near the surface is GMm/2R, which equals the orbital kinetic energy there.

Why is the answer always positive even though both energies are negative?

E_orbit and E_surface are both negative, but E_orbit (a smaller negative, closer to zero) is larger than E_surface. So E_orbit − E_surface is positive. A positive value makes sense because you must supply energy to lift and speed up the satellite.

Do we include Earth's rotation in NEET problems?

No. For NEET the satellite is taken as at rest on the surface (KE = 0). Earth's spin gives a small real-world boost but is ignored in the standard formula, so E_surface = −GMm/R.

How does minimum launch energy compare with escape energy?

Escape energy from the surface is GMm/R (final energy = 0). Launch-into-orbit energy is always less than this, because the satellite ends in a bound orbit with negative energy, not at infinity.